Instructions Determine the height of the fluid in the reservoir at time, t = 2.5 seconds, Properly label the iterations. Take note of the tolerance value and criteria. given that the velocity at the outfall, v(t) = 3 m/s, the acceleration due to gravity, g = 9.81 m/s² and the length of the pipe to outfall, L = 1.5 meters. A friendly reminder: The equation involved Reservoir v(t) V2gh = tanh V2gh) h water Pipe is hyperbolic tangent. This is not tan (h)(t/2L * sqrt(2gh)) - v (1) Hint: Transform the equation to a L function of form: f(h) = 0 Solve MANUALLY using BISECTION AND REGULA-FALSI METHODS, starting at x1eft = 0.1, Xfight| = 1, ɛ = 0.001 and |f(xnew)l < ɛ Note: We are expected to get a value of h around 0.47. The number of significant digits that we will be reporting depends on the tolerance value and iteration criterion set.