Instruction: Encircle the letter that corresponds to the best answer and show your solution. 1. Find the equation of the tangent line to the circle x² + y² – 12x + 4y – 5 = 0 at point (0,1) а. у%3D 2х + 2 с. у %3Dх — 2

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Differential Calculus

Instruction: Encircle the letter that corresponds to the best answer and show your solution.
1. Find the equation of the tangent line to the circle x² + y² – 12x + 4y – 5 = 0 at point (0,1).
а. у%3D 2х + 2
b. y = 2x + 1
-
c. y = x – 2
d. y = -4x – 2
Transcribed Image Text:Instruction: Encircle the letter that corresponds to the best answer and show your solution. 1. Find the equation of the tangent line to the circle x² + y² – 12x + 4y – 5 = 0 at point (0,1). а. у%3D 2х + 2 b. y = 2x + 1 - c. y = x – 2 d. y = -4x – 2
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