Instruction: Determine the area and draw the normal curve of the following z values below. 1. From z 0 to z = 1.32 2. From z 2.78 to z = 2.91 Instruction: Covert the following in z scores and construct the normal curve
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A: NOTE: Since there are multiple subparts, we have solved the first three subparts for you. To get the…
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A: Solution: x(1) Frequency (f)(2) f⋅d(4)=(2)×(3) cf(6) 50 2 -2 -4 2 60 5 -1 -5 7 70=A 9 0 0…
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Q: Use the stem-and-leaf plot below to determine the five number summary for the data. Stem Leaves…
A: First let us create the data set from the stem and leaf plot. 2,2,3,5,7,13,15,16,20,21,24,26 5 point…
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A: For normal distribution, the mean is equal to 0
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A: Hi! Thank you for the question, As per the honor code, we are allowed to answer one question at a…
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Q: The table below gives the marks awarded for an assignment and their frequencies in a class of 12…
A: Mean = (summation fiXi)/(summation (fi) = (3*2+8*5+9*4+10*1)/(2+5+4+1) = 7.67
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Q: Use the data in the table to the right to answer the following questions. Weights (g) of a Sample…
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Q: Use the data in the table to the right to answer the following questions. Weights (g) of a Sample…
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- Find the median, quartiles, minimum, maximum, range, and IQR of the following scores out of 100 on an exam:20. Find the geometric mean for the following data: variable X: 2 3 6. Frequency: 10 15 18 12 1. 4 7Use the data in the table to the right to answer the following questions. Weights (g) of a Sample Bag of Candy Red Blue Brown Green Yellow 0.964 0.793 0.784 0.814 0.966 0.708 0.991 0.845 0.771 0.733 Find the sample proportion of candy that are red. 0.747 0.886 0.782 0.793 0.882 0.766 0.766 0.919 0.923 0.975 0.849 The proportion of red candy = 0.958 0.762 0.712 0.938 0.752 0.915 (Type an integer or decimal rounded to three decimal places as needed.) 0.822 0.844 0.733 0.781 0.976 0.955 0.827 0.939 0.818 0.805 0.812 0.725 0.966 0.815 0.854 0.915
- The following set of data represents the number of orders filled by a national-chain restaurant during a two week period. Construct a five number summary for the the data. 66, 75, 68, 89, 86, 73, 67, 75, 75, 82, 85, 74, 67, 61 (Round to the nearest hundredth, if needed). Min _________________ Lower Quartile _________________ Median __________________ Upper Quartile _________________ Maximum __________________ What is the range and the interquartile range (IQR)? Range __________________ Interquartile Range (IQR) ___________________Draw a box plot for the data set with the statistics in the pictureDerby collects samples of insects in the forest and in a marsh to count the number of insects in each sample and then releases the insects. The number of insects in each sample from the two locations is provided below. Forest 1515 1313 1414 99 1616 1111 1515 1414 1515 1414 Marsh 1717 1414 1515 1717 1616 1818 1717 1919 1313 1616 What is the median and the interquartile range for each of the two locations? Round to one decimal place. The median number of insects in the forest samples is , and the interquartile range is . The median number of insects in the marsh samples is , and the interquartile range is .
- Below are the heights (in inches) of a sample of football players. Graph the boxplot and find the values for each of the quartiles and outlier(s), if they exist. (10 points for total) Students use the data below to calculate: 85 83 79 55 70 775 89 76 28. Smallest value= Q1= Q2= Q3= Largest value= 87 88 88 85 86 Outlier(s) Draw the Boxplot inside the box and label all values:What is the zscore for: data= 31 mean =39 Sx= 3.7 O 2.16 O -2.16 О 3.7 O -3.7Using the following stem & leaf plot, find the five number summary for the data. 0 2 3 4 4 5 9 3 4 2 2 79 0 45 6 89 6 0 8 Min = Q1 Med = Q3 = %3D Max =
- I vacuum cleaners. The weights are classified according to vacuum cleaner type. At a=0.10, can you conclude that at least one mean vacuum cleaner weight is different The table available below shows the weights (in pounds) for a sample from the others? E Click the icon to view the vacuum cleaner weight data. Let Hgu. PBLU and PTC represent the mean weights for bagged upright, bagless upright, and top canister vacuums respectively. What are the hypotheses for this test? O A. Ho: Heu * PBLU HTC H PBU PBLU =HTC Weight of Vacuum Cleaners by Type O B. Ho: At least one of the means is different. H PBu = HBLUu =PTC &c. Họ: PBU = HBLU =HTC Bagged upright 22 19 Bagless upright Top canister 21 22 23 25 H: At least one of the means different. 17 20 15 18 18 19 O D. Ho: PBU = PBLU "HTC 23 20 26 25 22| 23 Ha: Peu * PBLU *HTC What is the test statistic? Print Done F= (Round to two decimal places as needed.)How do I interpret the 6 characteristics whith the data given? Column Mean Median Range Variance Std. dev. 1 - Cholesterol 253.92857 268 218 2276.291 47.710492