Instead of using the values {1,2,3,4,5,6} on dice, suppose a pair of dice have the following: {1,2,2,3,3,4} on one die and {1,3,4,5,6,8) on the other. Find the probability of rolling a sum of 12 with these dice. Be sure to reduce. 1 [?]
Instead of using the values {1,2,3,4,5,6} on dice, suppose a pair of dice have the following: {1,2,2,3,3,4} on one die and {1,3,4,5,6,8) on the other. Find the probability of rolling a sum of 12 with these dice. Be sure to reduce. 1 [?]
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![### Probability Exercise
#### Problem Statement:
Instead of using the values {1,2,3,4,5,6} on dice, suppose a pair of dice have the following:
- First Die: {1, 2, 2, 3, 3, 4}
- Second Die: {1, 3, 4, 5, 6, 8}
Find the probability of rolling a sum of 12 with these dice. Be sure to reduce your answer.
#### Solution:
To determine the probability of rolling a sum of 12 with these dice, follow these steps:
1. **Identify all possible outcomes:**
- Each die has 6 faces, so there are \(6 \times 6 = 36\) possible outcomes when rolling these two dice.
2. **Determine the combinations that result in a sum of 12:**
- We need to find pairs \((x, y)\), where \(x\) comes from the first die and \(y\) comes from the second die such that \(x + y = 12\).
- By inspecting the values:
- The possible combination is (4, 8) since 4 from the first die and 8 from the second die adds up to 12.
3. **Count the favorable outcomes:**
- The pair (4, 8) is the only combination that results in a sum of 12.
- Since each die has exactly one face showing 4 and one face showing 8, this combination occurs exactly once.
4. **Calculate the probability:**
- The probability \( P \) of rolling a sum of 12 is the number of favorable outcomes divided by the total number of possible outcomes.
\[
P = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{1}{36}
\]
Therefore, the probability of rolling a sum of 12 with these dice is \( \frac{1}{36} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F66c912c6-a327-4873-9511-a364c6ae7474%2Ff69271ac-2640-4388-bc3a-e471b5275bfe%2F66c8a9h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Probability Exercise
#### Problem Statement:
Instead of using the values {1,2,3,4,5,6} on dice, suppose a pair of dice have the following:
- First Die: {1, 2, 2, 3, 3, 4}
- Second Die: {1, 3, 4, 5, 6, 8}
Find the probability of rolling a sum of 12 with these dice. Be sure to reduce your answer.
#### Solution:
To determine the probability of rolling a sum of 12 with these dice, follow these steps:
1. **Identify all possible outcomes:**
- Each die has 6 faces, so there are \(6 \times 6 = 36\) possible outcomes when rolling these two dice.
2. **Determine the combinations that result in a sum of 12:**
- We need to find pairs \((x, y)\), where \(x\) comes from the first die and \(y\) comes from the second die such that \(x + y = 12\).
- By inspecting the values:
- The possible combination is (4, 8) since 4 from the first die and 8 from the second die adds up to 12.
3. **Count the favorable outcomes:**
- The pair (4, 8) is the only combination that results in a sum of 12.
- Since each die has exactly one face showing 4 and one face showing 8, this combination occurs exactly once.
4. **Calculate the probability:**
- The probability \( P \) of rolling a sum of 12 is the number of favorable outcomes divided by the total number of possible outcomes.
\[
P = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{1}{36}
\]
Therefore, the probability of rolling a sum of 12 with these dice is \( \frac{1}{36} \).
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