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Instead of 0.q, you have to use my student ID using the last 3 digits. If the last 3 digits of my student ID are 495.q use 495 instead. Question 2: Equivalent Nodal Forces of 2-D Plane Finite Elements ( For the four-node linear plane element shown below with a uniform surface traction along its side 2-3. You are required to evaluate the force matrix by using the energy equivalent nodal forces. Let the thickness o the element be t= 10 + 0.q mm. 3 T = 20 + 0.q N/mm? (0, 4) (5, 4)

Instead of 0.q, you have to use my student ID using the last 3 digits. If the last 3 digits of my student ID are 495.q use 495 instead. Question 2: Equivalent Nodal Forces of 2-D Plane Finite Elements ( For the four-node linear plane element shown below with a uniform surface traction along its side 2-3. You are required to evaluate the force matrix by using the energy equivalent nodal forces. Let the thickness o the element be t= 10 + 0.q mm. 3 T = 20 + 0.q N/mm? (0, 4) (5, 4)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Instead of 0.q, you have to use my student ID using the last 3 digits. If the last 3 digits of my student ID are 495.q use 495 instead. Question 2: Equivalent Nodal Forces of 2-D Plane Finite Elements ( For the four-node linear plane element shown below with a uniform surface traction along its side 2-3. You are required to evaluate the force matrix by using the energy equivalent nodal forces. Let the thickness of the element be t= 10 + 0.q mm. T = 20 + 0.q N/mm2 (0, 4) (5, 4) (0, 0) (8, 0) 1 2
Transcribed Image Text:Instead of 0.q, you have to use my student ID using the last 3 digits. If the last 3 digits of my student ID are 495.q use 495 instead. Question 2: Equivalent Nodal Forces of 2-D Plane Finite Elements ( For the four-node linear plane element shown below with a uniform surface traction along its side 2-3. You are required to evaluate the force matrix by using the energy equivalent nodal forces. Let the thickness of the element be t= 10 + 0.q mm. T = 20 + 0.q N/mm2 (0, 4) (5, 4) (0, 0) (8, 0) 1 2
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