Inside a bag there are 3 green balls, 2 red balls and 2 yellow balls. Two balls are randomly drawn without replacement. Calculate the probability of drawing one green ball and one yellow ball. The tree diagram has been started.
Inside a bag there are 3 green balls, 2 red balls and 2 yellow balls. Two balls are randomly drawn without replacement. Calculate the probability of drawing one green ball and one yellow ball. The tree diagram has been started.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Inside a bag there are 3 green balls, 2 red balls and 2 yellow balls. Two balls are randomly drawn without replacement. Calculate the

Transcribed Image Text:This image shows a tree diagram used to represent probabilities related to a specific event, involving colors labeled G, R, and Y.
### Description:
1. **Initial Branches:**
- The diagram begins with a single point branching into three lines representing three different outcomes in the first event.
- The branch labeled "G" has a probability of \( \frac{3}{7} \).
- The branch labeled "R" has a probability of \( \frac{2}{7} \).
- The branch labeled "Y" has a probability of \( \frac{2}{7} \).
2. **Secondary Branches (Starting from G):**
- The "G" branch further splits into three outcomes:
- Another "G" with a probability of \( \frac{2}{6} \).
- An "R" with a probability of \( \frac{2}{6} \).
- A "Y" with a probability of \( \frac{2}{6} \).
This tree diagram effectively lays out the pathway and corresponding probabilities for a sequence of events concerning the selection of colors. It is a visual method to help in calculating the probabilities of combined events.
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