Insert the integers 1 through 7 into an AVL tree, showing each step and rotation.

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Insert the integers 1 through 7 into an AVL tree, showing each step and rotation.

 

Is what I have wrong? If not could provide correct solution?

The image contains a series of diagrams illustrating binary tree transformations with a focus on the balance factor. The steps are as follows:

1. Start with node 7:
   - A node labeled "7" with a left child "3".
   
2. Add a child node to 3:
   - The node "3" gains a left child "2".
   
3. Balance the tree:
   - The node "2" becomes the root with left child "1" and right child "3".
   
4. Expansion:
   - Node "3" gets a right child "7".
   - Node "7" becomes a right child to "1".
   - A right child "5" is added to "3".

5. Further modifications by adding node "6":
   - New node "6" added as a right child of "5".
   
6. The adjustments are demonstrated through rotations:
   - "Left-right" and "right-left" rotations are illustrated.
   
7. Two different configurations are circled and labeled:
   - One labeled as "Final" and the other "root -2->1".

- The steps include annotations about left and right rotations with corresponding balance factor adjustments written as "0-2->-2" and "1 right rot".

- The diagrams illustrate how to maintain balance in a binary search tree through rotations, particularly left-right and right-left rotations.
Transcribed Image Text:The image contains a series of diagrams illustrating binary tree transformations with a focus on the balance factor. The steps are as follows: 1. Start with node 7: - A node labeled "7" with a left child "3". 2. Add a child node to 3: - The node "3" gains a left child "2". 3. Balance the tree: - The node "2" becomes the root with left child "1" and right child "3". 4. Expansion: - Node "3" gets a right child "7". - Node "7" becomes a right child to "1". - A right child "5" is added to "3". 5. Further modifications by adding node "6": - New node "6" added as a right child of "5". 6. The adjustments are demonstrated through rotations: - "Left-right" and "right-left" rotations are illustrated. 7. Two different configurations are circled and labeled: - One labeled as "Final" and the other "root -2->1". - The steps include annotations about left and right rotations with corresponding balance factor adjustments written as "0-2->-2" and "1 right rot". - The diagrams illustrate how to maintain balance in a binary search tree through rotations, particularly left-right and right-left rotations.
Expert Solution
Step 1: Defining Introduction

The AVL Trees are BST with height balance property. The balance factor of the nodes should be (-1, 0, or 1). Balance factor is calculated as height of left subtree - height of right subtree (OR) height of right subtree - height of left subtree.

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