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The while loop makes multiple attempts to read a nonnegative integer from input into userAge. Use multiple exception handlers to: Catch an InputMismatchException, output "Unexpected input: The UserAge program quits", and assign retry with false. • Catch an Exception and output the message of the Exception. End each output with a newline. Ex: If the input is 44, then the output is: Valid input: User's age is 44 Ex: If the input is L, then the output is: Unexpected input: The UserAge program quits Ex: If the input is -65 44, then the output is: User's age must be nonnegative Valid input: User's age is 44 1 import java.util.Scanner; 2 import java.util.InputMismatchException; L234567800 4 public class UserAge { 9 10 AWNHO 11 12 13 14 15 16 17 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int userAge; boolean retry = true; while (retry) { try { userAge = scnr.nextInt (); if (userAge< 0) { throw new Exception ("User's age must be nonnegative"); }

The while loop makes multiple attempts to read a nonnegative integer from input into userAge. Use multiple exception handlers to: Catch an InputMismatchException, output "Unexpected input: The UserAge program quits", and assign retry with false. • Catch an Exception and output the message of the Exception. End each output with a newline. Ex: If the input is 44, then the output is: Valid input: User's age is 44 Ex: If the input is L, then the output is: Unexpected input: The UserAge program quits Ex: If the input is -65 44, then the output is: User's age must be nonnegative Valid input: User's age is 44 1 import java.util.Scanner; 2 import java.util.InputMismatchException; L234567800 4 public class UserAge { 9 10 AWNHO 11 12 13 14 15 16 17 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int userAge; boolean retry = true; while (retry) { try { userAge = scnr.nextInt (); if (userAge< 0) { throw new Exception ("User's age must be nonnegative"); }

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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## Handling User Input with Exception Handling in Java The while loop makes multiple attempts to read a nonnegative integer from input into `userAge`. Use multiple exception handlers to: - Catch an `InputMismatchException`, output "Unexpected input: The UserAge program quits", and assign `retry` with false. - Catch an `Exception` and output the message of the Exception. End each output with a newline. ### Example Outputs - **If the input is 44**, then the output is: ``` Valid input: User's age is 44 ``` - **If the input is 'L'**, then the output is: ``` Unexpected input: The UserAge program quits ``` - **If the input is -65 44**, then the output is: ``` User's age must be nonnegative Valid input: User's age is 44 ``` ### Java Code Implementation ```java import java.util.Scanner; import java.util.InputMismatchException; public class UserAge { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int userAge; boolean retry = true; while (retry) { try { userAge = scnr.nextInt(); if (userAge < 0) { throw new Exception("User's age must be nonnegative"); } } catch (InputMismatchException e) { System.out.println("Unexpected input: The UserAge program quits"); retry = false; } catch (Exception e) { System.out.println(e.getMessage()); userAge = scnr.nextInt(); System.out.println("Valid input: User's age is " + userAge); retry = userAge >= 0; } } } } ``` This program guides the user to input a valid nonnegative age. It uses exception handling to manage different types of input errors, ensuring robust input processing.
Transcribed Image Text:## Handling User Input with Exception Handling in Java The while loop makes multiple attempts to read a nonnegative integer from input into `userAge`. Use multiple exception handlers to: - Catch an `InputMismatchException`, output "Unexpected input: The UserAge program quits", and assign `retry` with false. - Catch an `Exception` and output the message of the Exception. End each output with a newline. ### Example Outputs - **If the input is 44**, then the output is: ``` Valid input: User's age is 44 ``` - **If the input is 'L'**, then the output is: ``` Unexpected input: The UserAge program quits ``` - **If the input is -65 44**, then the output is: ``` User's age must be nonnegative Valid input: User's age is 44 ``` ### Java Code Implementation ```java import java.util.Scanner; import java.util.InputMismatchException; public class UserAge { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int userAge; boolean retry = true; while (retry) { try { userAge = scnr.nextInt(); if (userAge < 0) { throw new Exception("User's age must be nonnegative"); } } catch (InputMismatchException e) { System.out.println("Unexpected input: The UserAge program quits"); retry = false; } catch (Exception e) { System.out.println(e.getMessage()); userAge = scnr.nextInt(); System.out.println("Valid input: User's age is " + userAge); retry = userAge >= 0; } } } } ``` This program guides the user to input a valid nonnegative age. It uses exception handling to manage different types of input errors, ensuring robust input processing.
The image contains a snippet of Java code designed to obtain and validate a user's age input. Below is a detailed transcription of the code: ```java while (retry) { try { userAge = scnr.nextInt(); if (userAge < 0) { throw new Exception("User's age must be nonnegative"); } retry = false; System.out.print("Valid input: "); System.out.println("User's age is " + userAge); } } ``` ### Code Explanation: - **Lines 9-24**: This is a loop that continues to execute as long as `retry` is true. - **Line 11**: The code attempts to read an integer input for `userAge` using `scnr.nextInt()` within a `try` block to handle potential input errors. - **Line 13-15**: An `if` statement checks if the `userAge` is negative. If it is, the code throws an exception with the message, "User's age must be nonnegative," preventing the program from proceeding with negative input. - **Line 18**: If the input is valid (nonnegative), `retry` is set to false, terminating the loop. - **Line 19-20**: The code prints "Valid input: ", followed by the user's age, indicating successful validation and capturing of user's age. This example demonstrates basic exception handling in Java, ensuring that the user inputs a nonnegative age.
Transcribed Image Text:The image contains a snippet of Java code designed to obtain and validate a user's age input. Below is a detailed transcription of the code: ```java while (retry) { try { userAge = scnr.nextInt(); if (userAge < 0) { throw new Exception("User's age must be nonnegative"); } retry = false; System.out.print("Valid input: "); System.out.println("User's age is " + userAge); } } ``` ### Code Explanation: - **Lines 9-24**: This is a loop that continues to execute as long as `retry` is true. - **Line 11**: The code attempts to read an integer input for `userAge` using `scnr.nextInt()` within a `try` block to handle potential input errors. - **Line 13-15**: An `if` statement checks if the `userAge` is negative. If it is, the code throws an exception with the message, "User's age must be nonnegative," preventing the program from proceeding with negative input. - **Line 18**: If the input is valid (nonnegative), `retry` is set to false, terminating the loop. - **Line 19-20**: The code prints "Valid input: ", followed by the user's age, indicating successful validation and capturing of user's age. This example demonstrates basic exception handling in Java, ensuring that the user inputs a nonnegative age.
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input:     -65 44

Input:    -37 -39 H -25 -5 -54

 

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