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initial value problem has a unique solution. 1 dy x² + y² dx = x, y(0) = 1. = The theorem implies the existence of a unique solution because x³ + xy² and continuous in some rectangular region containing the point (0, 1). (³+²) By O The theorem does not imply the existence of a unique solution because 8(1) dy The theorem does not imply the existence of a unique solution because x³ + xy2 is not continuous in any rectangular region containing the point (0, 1). are is continuous but ³+² is not continuous in any rectangular region containing the point (0, 1).

initial value problem has a unique solution. 1 dy x² + y² dx = x, y(0) = 1. = The theorem implies the existence of a unique solution because x³ + xy² and continuous in some rectangular region containing the point (0, 1). (³+²) By O The theorem does not imply the existence of a unique solution because 8(1) dy The theorem does not imply the existence of a unique solution because x³ + xy2 is not continuous in any rectangular region containing the point (0, 1). are is continuous but ³+² is not continuous in any rectangular region containing the point (0, 1).

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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initial value problem has a unique solution. 1 dy x² + y² dx = x, y(0) = 1. = The theorem implies the existence of a unique solution because x³ + xy² and continuous in some rectangular region containing the point (0, 1). a+² dy O The theorem does not imply the existence of a unique solution because 8(- The theorem does not imply the existence of a unique solution because x³ + xy is not continuous in any rectangular region containing the point (0, 1). تران ایر (x³+x²) By 1 are is continuous but is not continuous in any rectangular region containing the point (0, 1).
Transcribed Image Text:initial value problem has a unique solution. 1 dy x² + y² dx = x, y(0) = 1. = The theorem implies the existence of a unique solution because x³ + xy² and continuous in some rectangular region containing the point (0, 1). a+² dy O The theorem does not imply the existence of a unique solution because 8(- The theorem does not imply the existence of a unique solution because x³ + xy is not continuous in any rectangular region containing the point (0, 1). تران ایر (x³+x²) By 1 are is continuous but is not continuous in any rectangular region containing the point (0, 1).
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