- (In(In(Inx))) dx (A In(In(Inx)) B xlnxln( Inx) xIn(Inx) D x(Inx)²

Q: S 3 (x + 1)(x² + x) -dx

A:

Q: (x² + y³ )dx + 2xydy = 0

A: TO SOLVE THE GIVEN  DIFFERENTIAL EQUATION

Q: (1.) -|w4+1W ✓ 6 =dx 2 9 - 4x

A: Since you have asked multiple question is one window and as per guideline only one question is…

Q: dy = 2x(1+y²) ex²

A:

Q: d (9x² – 4x' - 12) 5 (a) dx

A:

Q: Suppose that f(x) = (x - 4)*.

A: At the point of inflection, f''(x)=0.

Q: Evaluate f -dx is equal to x In 3x

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Q: The function re* sin(8x) is annihilated by the operator

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Q: Evaluate: [3. 3x sec² (³) dr = [

A:

Q: (4) fxe-x dx

A: Given: ∫xe-xdx

Q: [f(a)]² =

A:

Q: d/dx [(2x+1)3(3x2-1)4]

A:

Q: erify the result C(X"X) = C(X") for %3D x-(; ) X = -1 0 %3D

A: We have to solve given problems:

Q: Determine Dx[x(x-2)²]

A:

Q: flx)=x =X-5 (x)= Find .f)

A: Here, the given function is: f(x)=x-5, g(x)=x2

Q: xe* хе dx. J (x + 1)2

A:

Q: hᴏf(x)=

A: Solve the following

Q: -1)/(x4))1/2

A:

Q: [22] Express the function as a product by factoring the right-hand side: f(x)= x' +x² – 4.x - 4.

A: We have to express the given function as a product by factoring the right hand side: fx=x3+x2-4x-4…

Q: f(x5) (16-x²)³/² dx

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Q: y = (In x)*

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Q: 1-√x)³ 3 √x dx

A:

Q: dx 3 /x + Vx

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Q: [cx)= (x+1) 「cx)-(x_)[cxー1) (xー1)「cx-1) [(-x)= [(1-x) |

A: Γ(x)=∫0∞tx-1e-tdt  for x>0Γ(x+1)=∫0∞txe-tdt =-txe-t0∞+x∫0∞tx-1e-tdt=xΓ(x)⇒Γ(x)=Γ(x+1)x Now,…

Q: (In(æ)) -dx; 1

A: I=∫1eln(x)4xdx Now substitute:   ln(x)=t

Q: evaluate 1/(2x(x2-9)1/2 )dx    and what method did you use

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Q: IScmプa (4x)"dx

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Q: x2 - 10x - 5 dx J (x - 1)2(x² + 1)

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Q: • N/W [ (x³-3x) dx - 1

A:

Q: Compute each of the following for the polynomial f(x)=−7x^8+7x^5+7x^3−6x. (a) f′(x)= (b) f′′(x)=…

A: We have f(x)=-7x8+7x5+7x3-6x (a) Now Differentiate with respect to "x"…