Information: Rats with one or two brown fur alleles are both phenotypically brown because brown is dominant. Rats with two Albino (white) alleles are phenotypically white. 2. Cross a heterozygous Brown male to a heterozygous Brown female Male parent genotype: Possible Sperm: Female parent genotype: Possible Eggs: offspring genotypes & ratios: offspring phenotypes & ratios:
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- Information: Rats with one or two brown fur alleles are both phenotypically brown because brown is dominant. Rats with two Albino (white) alleles are phenotypically white. 1. Cross a homozygous Brown male to a White female (she logically is homozygous) Male parent genotype: Possible Sperm: Female parent genotype: Possible Eggs: offspring genotypes & ratios: offspring phenotypes & ratios:From DNA to Protein and Inheritance Co-Dominance: In co-dominance, the heterozygous individual exhibits the phenotype for both alleles. We used the ABO blood groups as an example of co-dominance. 8. What potential blood types can be present in the offspring if two type "O" mate with one another? (alams 1) Ilgq xal Ligg 9. What are the potential blood types present in the offspring if two parents with type A blood mate with each other? parents 10. What are the potential blood types for offspring that are produced by a parent that is A+ and one that is AB-? Sgningatlo odi nol om sig gonda borooqxs Post-Lab Questions 1. In the human species, polydactyly (theDirection: Answer the following problems: 1. Predict the phenotypic ratios of offspring when a homozygous white cow is crossed with a roan bull. Illustrate using a Punnett square. 2. Complete the Punnett square for a cross between a black chicken (BB) and a white chicken (WW). Give the phenotype of the offspring in the F1 generation. Кey BB – black ww- white F1 BW – checkered Phenotype:
- 5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? a. Possible genotypes for Polled condition: Horned: b. Possible genotypes for Red coat:White Coat: Roan Coat: c. Male genotype Male possible gametes: Female genotypeFemale possible gametes: e. f. Genotypic Ratio: g. Phenotypic Ratio:5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? Horned: r: Roan Coat: a. Possible genotypes for Polled condition Coat:_ ossible geno c. Male genotype: d. Female genotype: Male possible gametes Female possible gametes e. f. Genotypic Ratio: g. Phenotypic Ratio 5B, Breed two of the F1 generation to determine the possibilities in the F2 generation. Horned: a. Possible genotypes for Polled condition b. Possible genotypes for Red coat: White Coat:_ Roan Coat: c. Male genotype: d. Female genotype Male possible gametes Female possible gametes: f. Genotypic Ratio: g. Phenotypic Ratiodd-ons Help в I U A Calibri 12 三 三1 |:三 6. Consider a guinea pig with a homozygous genotype and a white fur color phenotype. a. What is the probability this parent will produce a gamete with the dominant allele? b. What is the probability this parent will produce a gamete with the recessive allele? C. If 31 sperm cells are collected from this guinea pig, how many would you expect to have the recessive allele (as determined by sequencing the gene)? !!!
- For numbers 1-9. Cross the following blood type of the wife and husband and answer the questions provided. Wife: Type A Husband: Type AB 1-3. What are the possible genotype of the offspring? А. АО, ВО В. А, ВО, АВ С. АО, ВВ D. AA,AB 4-6. What are the possible Phenotype? A. Type A and B В. Туре АВ С. Туре А, В аnd AB D. Type A, B and O 7-9. What is the percentage of type AB if the genotype you cross is AO and AB? А. 25% В. 50% C. 75% D. 0%Incomplete Dominance: These alleles do not show dominance or recessiveness. The het- erozygous individual will produce a phenotype that is intermediate to both the homozy- gous dominant and homozygous recessive. 7. An armadillo with a normal tail length (long) is mated with a tailless armadillo and all of the offspring are short tailed. When two short-tailed armadillos are mated with each other it results in a 1:2:1 ratio of normal tail length: short-tailed: tailless armadillos. a. What is the genotype for a long-tailed armadillo? ENDYSTING b. What is the genotype for a short-tailed armadillo? C. What is the genotype for a tailless armadillo? d. What phenotypic ratio would you expect if a normal-tailed armadillo was mated with a short-tailed armadillo? e. What phenotypic ratio would you expect if a short-tailed armadillo was mated with a tailless armadillo?1. Two normal visioned parents have a color-blind son. Give the genotype of both parents and the son. 2. In cats, the allele (B) produces black color but (b) produces a yellow color. These alleles are incompletely dominant to each other. A heterozygote produces a tortoise shell color. The alleles (B) and (b) are sex-linked as well. Cross a tortoise shell female with a yellow male. a. What percent of their offspring will be yellow? b. What percent of their offspring will be black? c. What percent of their offspring will be tortoise shell? d. Why is it impossible to have a tortoise shell male offspring?
- O e. Parent 2: Parent 1: Parent 2: ¡Ai QUESTION 9 Bi QUESTION 8 Let's assume that, in dragons, red scales (B) are dominant to green scales (b), and long tongues (S) are dominant to short tongues (s). The genes that determine these characteristics assort independently. A homozygous red, long-tongued dragon is crossed with a homozygous green, short-tongued dragon. If an F1 dragon is crossed to a homozygous green and homozygous short-tongued dragon, what phenotypes and proportions are expected in the offspring? O a. 100% green and long-tongued O b. ½ green and short-tongued & ½ red and long-tongued O c. ½ red and short-tongued & ½ green and long-tongued O d.% red and long-tongued, % red and short-tongued, ½ green and long-tongued, % green and short-tongued O e. 9/16 red, long-tongued, 3/16 green, long-tongued, 3/16 red, short-tongued, 1/16 green, short-tongued Save and Submit to save and submit. Click Save All Answers to save all answers. 000 MacBook Air9 The color of Andalusian chickens results from the inheritance of alleles that exhibit incomplete dominance. Black Andalusian chickens result when two alleles for melanin production are inherited (MM). White-splashed chickens result from the inheritance of two copies of a different allele (mm). The heterozygous condition (Mm) results in their famous bluish color. Predict the genotypes and phenotypes from the following crosses: MM X mm and Mm x Mm. a. genotype of male b. genotype of female c. genotypes of offspring d. phenotypes of offspring e. genotype of male f. genotype of female g. genotypes of offspring h. phenotypes of offspring3.In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). Cross a marriage between a heterozygous spotted, non-wooly man with a heterozygous wooly-haired, non-spotted woman. Give genotypic and phenotypic ratios of offspring.