∞ Σ(n − 1)cn-1x² = − 1 − x + co +€₁x + Σcnx". n=2 n=2 Because the left-hand side contains neither a constant term nor a term containing x to the first power, the identity principle now yields co = 1, c₁ = 1, and Cn = (n − 1)cn-1 for n ≥ 2. It follows that - C2 1. C₁ = 1!, ∞ C3: = 2. C₂ = 21, C4 = 3. c3 = 3!,

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I'm not following how the sum expression on top leads to the constants being factorial expressions on the bottom.

Please break it down so an ignorant person like me can understand it.

Thank you.

∞
Σ(n − 1)cn-1x² = −1− x + co + ₁x + Σ
n=2
n=2
Cản
Because the left-hand side contains neither a constant term nor a term containing
x to the first power, the identity principle now yields co = 1, ₁ = 1, and C₂ =
(n-1)Cn-1 for n 2. It follows that
C₂ = 1·C₁ = 1!, C3 = 2 C₂ = 2!,
C2
.
C4 = 3· C3 = 3!,
Transcribed Image Text:∞ Σ(n − 1)cn-1x² = −1− x + co + ₁x + Σ n=2 n=2 Cản Because the left-hand side contains neither a constant term nor a term containing x to the first power, the identity principle now yields co = 1, ₁ = 1, and C₂ = (n-1)Cn-1 for n 2. It follows that C₂ = 1·C₁ = 1!, C3 = 2 C₂ = 2!, C2 . C4 = 3· C3 = 3!,
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