Individuals were randomly assigned to 3 different online games. The mean hours/week spent on each of the three games are listed below: Online Games (mean hours per week) DragonQuest 33 35 FinalFantasy Ragnarok 28 33 30 28 36 30 30 29 38 34 a. Fill out the ANOVA table Sources of Variation |Treatment Error Total SS Mean Square F DF b. Use 75% confidence level to test for differences among happiness levels for the three types of browsers. Follow the steps for hypothesis testing. c. Now, this time apply the critical value approach only, given a .025 level of significance. What is your conclusion?

Individuals were randomly assigned to 3 different online games. The mean hours/week spent on each of the three games are listed below: Online Games (mean hours per week) DragonQuest 33 35 FinalFantasy Ragnarok 28 33 30 28 36 30 30 29 38 34 a. Fill out the ANOVA table Sources of Variation |Treatment Error Total SS Mean Square F DF b. Use 75% confidence level to test for differences among happiness levels for the three types of browsers. Follow the steps for hypothesis testing. c. Now, this time apply the critical value approach only, given a .025 level of significance. What is your conclusion?

Name: Please answer the question in the attached picture below. Thank you. I
Uploaded: 2024-03-20T07:06:41.000Z
Channel: Bartleby
Description: Please answer the question in the attached picture below. Thank you. Individuals were randomly assigned to 3 different online games. The mean hours/week spent on each of the threegames are listed below:Online Games (mean hours per week)DragonQuest333

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section: Chapter Questions

Problem 25SGR

See similar textbooks

Related questions

Q: 4. Evaluate the following limit. Vr3 +9 2x2 -5x +3 if x 3,

Q: Complete the description of how to transform the graph of f(x) = x2 to obtain the graph of the…

Q: Kindly answer the questions in the attached photo.

A: 1. Conduct the appropriate statistical analyses to compare the reading ability for the two types of…

Q: R 22 Y 26 O RS = 18 %3D O RS = 24 %3D O RS = 20 O RS = 16 %3D

Q: tions are half cut out due to the website's formatting. Could you attach a picture of your work?…

A: The instructor shoots free throws on a basketball court. The instructor hits the first and misses…

Q: Kindly answer the questions in the attached photos.

A: 3.The Interpretation of TablesThe Mauchly Test of Sphericity Null Hypothesis: Sphericity holds; the…

Q: Write the product as a sum. sin(8x) cos(9x)

A: Since you have asked multiple questions in a single request, we will be answering only the 1st…

Q: 1) The National Health Statistics Reports dated Oct. 22, 2008, included the following information on…

A: NOTE: Since you have asked multiple questions. The Answer for the first question is provided here.…

Q: please can you continue to answer for the remaining d, e, and f?

A: PR is a diameter of the given circle and mRW⏜ =55. So far, we have calculated the following:1…

Concept explainers

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.

Topic Video

Question

Please answer the question in the attached picture below. Thank you.

Individuals were randomly assigned to 3 different online games. The mean hours/week spent on each of the three
games are listed below:
Online Games (mean hours per week)
DragonQuest
33
35
FinalFantasy
Ragnarok
33
30
28
36
28
30
30
29
38
34
a. Fill out the ANOVA table
|Sources of Variation
SS
DF
Mean Square
F
Treatment
Error
| Total
b. Use 75% confidence level to test for differences among happiness levels for the three types of browsers. Follow the
steps for hypothesis testing.
c. Now, this time apply the critical value approach only, given a .025 level of significance. What is your conclusion?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 5 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Discrete Probability Distributions$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

Periodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services (2000 Merrill Lynch Client Satisfaction Survey). Higher ratings on the client satisfaction survey indicate better service with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use = .05 and test to see whether the consultant with more experience has the higher population mean service rating. Consultant A Consultant B = 16 = 10 = 6.82 = 6.25 = 0.58 = 0.7 State the null and alternative hypotheses.H0: 1 - 2 Selectgreater than 0greater than or equal to 0less than 0less than or equal to 0equal to 0not equal to 0Item 1Ha: 1 - 2 Selectgreater than 0greater than or equal to 0less than 0less than or equal to 0equal to 0not equal to 0Item 2 Compute the value of the test statistic (to 2 decimals).…
A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in Utah and Oregon. Due to recent trends in the childcare industry, the firm suspects that the mean annual income of childcare workers in Utah is less than the mean annual income of childcare workers in Oregon. To see if this is true, the firm selected a random sample of 20 childcare workers from Utah and an independent random sample of 20 childcare workers from Oregon and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars 27060 , 42320, 36445 , 37895 , 44564 , 35325 , 30313 , 28698 , 33706, 48365 , 26946 , 25063 , 28339 , 29265 , 40051 37026 , 40150, 42753 Utah 27820, 39471 29769, 48859, 32480 , 36288 45102 , 46219 , 51098 , 45516 , 38834 44659 , 40755 , 38006 , 39947 , 29801, 32200 38731 , 41370 , 28059 , 33753 , 35271 Oregon Send data to calc... v Send data to Excel The population standard deviation for the annual incomes of childcare…
A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in Utah and Oregon. Due to recent trends in the childcare industry, the firm suspects that the mean annual income of childcare workers in Utah is less than the mean annual income of childcare workers in Oregon. To see if this is true, the firm selected a random sample of 20 childcare workers from Utah and an independent random sample of 20 childcare workers from Oregon and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars 27060 , 42320 , 36445 , 37895, 44564 , 35325 , 30313 , 28698, 33706 , 48365 , 26946 , 25063 , 28339 , 29265 , 40051 , 37026 , 40150 , 42753 , 27820, 39471 Utah 29769 , 48859 , 32480 , 36288,45102 , 46219 ,51098 , 45516 , 38834 , 44659 , 40755 , 38006 , 39947 , 29801 , 32200, 38731 , 41370 , 28059 , 33753 , 35271 Oregon Send data to calc... v Send data to Excel The population standard deviation for the annual incomes of…
A researcher wanted to find the best viewing distance for watching a TV screen. He recruited the following number of participants and asked them to evaluate their satisfaction of the viewing distance. Then, he conducted an ANOVA to see if there is any significant mean differences. Here are the number of participants by each group: Group 1 (4 feet) - 5 people Group 2 (7 feet) - 5 people Group 3 (10 feet) - 6 people Group 4 (13 feet) - 5 people Group 5 (16 feet) - 4 people Given the numbers as presented above, what is the degrees of freedom for within groups for this analysis? a. 4 b. 20 O c. 21 d. 25
Many employers are concerned about employees wasting time by surfing the Internet and e-mailing friends during work hours. The article "Who Goofs Off 2 Hours a Day? Most Workers, Survey Says" summarized data from a large sample of workers.+ Suppose that the CEO of a large company wants to determine whether the mean wasted time during an 8-hour workday for employees of her company is less than the mean of 120 minutes reported in the article. Each person in a random sample of 10 employees is asked about daily wasted time at work (in minutes). Participants would be guaranteed anonymity to obtain truthful responses. Suppose the resulting data are as follows. 133, 82, 97, 123, 109, 131, 77, 120, 84, 132 (a) Calculate the point estimate (in minutes) for the population mean. 108.8 ✔ min (b) Assume that the population standard deviation is known to be a = 54.8 minutes. We would like to estimate the population mean with 95% confidence. Calculate the margin of error (in minutes) of the point…
Each year, marketing and information firm J.D. Power and Associates surveys new car owners 90 days after they have purchased their cars. The data collected are used to rate auto brands (Toyota, Ford, and others) on initial quality and initial customer satisfaction. USA Today reported both the number of manufacturing defects per 100 vehicles and a satisfaction score for all 33 brands sold in the United States.† A research group decides to compare the mean number of defects for 2 specific models of cars, A and B, made this year by taking random samples of 100 cars of each model. (a) After collecting the data, the research group calculates a 95% confidence interval to estimate the difference in population means. In this case, what is the population? all cars for models A and B that were produced this yearthe defects all cars made this yearthe 100 cars from each model (b) Suppose the calculated confidence interval is (84, 92) number of defects. What is the value of the point…
A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in Texas and Virginia. Due to recent trends in the childcare industry, the firm suspects that the mean annual income of childcare workers in Texas is less than the mean annual income of childcare workers in Virginia. To see if this is true, the firm selected a random sample of 10 childcare workers from Texas and an independent random sample of 10 childcare workers from Virginia and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars Texas 32653, 40135, 41586, 29796, 26989, 28723, 42380, 27583, 28696, 36255 Virginia 42155, 37776, 39846, 39844, 40972, 41769, 46045, 41387, 37035, 41268 Send data to calculator Send data to Excel The population standard deviation for the annual incomes of childcare workers in Texas and in Virginia are estimated as 6100 and 6300, respectively. It is also known that both populations are approximately normally…