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indicated to the horizontal neutral axis. The girder is also supporting a mass of 5000kg 30kN 20kN GIRDER 45⁰ 60⁰ 5000K 30⁰ 40kN

indicated to the horizontal neutral axis. The girder is also supporting a mass of 5000kg 30kN 20kN GIRDER 45⁰ 60⁰ 5000K 30⁰ 40kN

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please solve sub-part- ii completely and accurate with correct calculations. Thank you!

Part 2: A girder shown below in figure 1 is subject to the following concurrent forces acting at angles indicated to the horizontal neutral axis. The girder is also supporting a mass of 5000kg 30kN 20kN GIRDER 45⁰ figure (1) 60⁰ 5000Kg 30⁰ gravity 9.81 : 40kN
Transcribed Image Text:Part 2: A girder shown below in figure 1 is subject to the following concurrent forces acting at angles indicated to the horizontal neutral axis. The girder is also supporting a mass of 5000kg 30kN 20kN GIRDER 45⁰ figure (1) 60⁰ 5000Kg 30⁰ gravity 9.81 : 40kN
force ii. Using analytical techniques i.e. use force resolution methods to determine the horizontal and Vertical component of each force present, then combine them vectorily to determine resultant created by the applied forces. ( magnitude and direction) buit of oupind tan(A+B) = iii Analvee the variation signs bas obutilonu al bait of sel Formulae & Identities for Trigonometry: argital wolod wode pobu A xe leven latositod sdt at bede topl sin(A+B) = sinAcosB + cosAsinB sin(A-B) = sinAcosB - cosAsinB cos(A+B) = cosAcosB - sinAsinB cos(A-B) = cosAcosB + sinAsinB sin2A = 2sinAcosA cos2A = cos²A-sin²A cos2A = 2cos²A-1 sin²A+ cos²A = 1 tan A + tan B 1-tan A tan B R sin(-a)= asin - bcos and tan2A = somongin sau murga emsa sill goized it and 2 tan A 1-tan² A R sin(+a)= asin + bcos IVIDA
Transcribed Image Text:force ii. Using analytical techniques i.e. use force resolution methods to determine the horizontal and Vertical component of each force present, then combine them vectorily to determine resultant created by the applied forces. ( magnitude and direction) buit of oupind tan(A+B) = iii Analvee the variation signs bas obutilonu al bait of sel Formulae & Identities for Trigonometry: argital wolod wode pobu A xe leven latositod sdt at bede topl sin(A+B) = sinAcosB + cosAsinB sin(A-B) = sinAcosB - cosAsinB cos(A+B) = cosAcosB - sinAsinB cos(A-B) = cosAcosB + sinAsinB sin2A = 2sinAcosA cos2A = cos²A-sin²A cos2A = 2cos²A-1 sin²A+ cos²A = 1 tan A + tan B 1-tan A tan B R sin(-a)= asin - bcos and tan2A = somongin sau murga emsa sill goized it and 2 tan A 1-tan² A R sin(+a)= asin + bcos IVIDA
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