Please solve sub-part- ii completely and accurate with correct calculations. Thank you! Part 2: A girder shown below in figure 1 is subject to the following concurrent forces acting at anglesindicated to the horizontal neutral axis. The girder is also supporting a mass of 5000kg30kN20kNGIRDER45⁰figure (1)60⁰5000Kg30⁰gravity 9.81:40kN forceii. Using analytical techniques i.e. use force resolution methods to determine the horizontal andVertical component of each force present, then combine them vectorily to determine resultantcreated by the applied forces. ( magnitude and direction)buit of oupindtan(A+B) =iii Analvee the variationsigns bas obutilonu al bait of selFormulae & Identities for Trigonometry: argital wolod wode pobu Axe leven latositod sdt at bede toplsin(A+B) = sinAcosB + cosAsinBsin(A-B) = sinAcosB - cosAsinBcos(A+B) = cosAcosB - sinAsinBcos(A-B) = cosAcosB + sinAsinBsin2A = 2sinAcosAcos2A = cos²A-sin²Acos2A = 2cos²A-1sin²A+ cos²A = 1tan A + tan B1-tan A tan BR sin(-a)= asin - bcosandtan2A =somongin sau murga emsa sill goized itand2 tan A1-tan² AR sin(+a)= asin + bcosIVIDA

Answered: Image /qna-images/answer/335643d7-0db6-40a3-872b-aeee1ef6e9d0.jpg

Answered: indicated to the horizontal neutral…

indicated to the horizontal neutral axis. The girder is also supporting a mass of 5000kg 30kN 20kN GIRDER 45⁰ 60⁰ 5000K 30⁰ 40kN

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

Please solve sub-part- ii completely and accurate with correct calculations. Thank you!

Part 2: A girder shown below in figure 1 is subject to the following concurrent forces acting at angles
indicated to the horizontal neutral axis. The girder is also supporting a mass of 5000kg
30kN
20kN
GIRDER
45⁰
figure (1)
60⁰
5000Kg
30⁰
gravity 9.81
:
40kN

force
ii. Using analytical techniques i.e. use force resolution methods to determine the horizontal and
Vertical component of each force present, then combine them vectorily to determine resultant
created by the applied forces. ( magnitude and direction)
buit of oupind
tan(A+B) =
iii Analvee the variation
signs bas obutilonu al bait of sel
Formulae & Identities for Trigonometry: argital wolod wode pobu A
xe leven latositod sdt at bede topl
sin(A+B) = sinAcosB + cosAsinB
sin(A-B) = sinAcosB - cosAsinB
cos(A+B) = cosAcosB - sinAsinB
cos(A-B) = cosAcosB + sinAsinB
sin2A = 2sinAcosA
cos2A = cos²A-sin²A
cos2A = 2cos²A-1
sin²A+ cos²A = 1
tan A + tan B
1-tan A tan B
R sin(-a)= asin - bcos
and
tan2A =
somongin sau murga emsa sill goized it
and
2 tan A
1-tan² A
R sin(+a)= asin + bcos
IVIDA

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