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Indicate the major organic products from the reaction shown. NaOH Br2 (excess)

Indicate the major organic products from the reaction shown. NaOH Br2 (excess)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Transcription for Educational Website:** **Title: Determining Major Organic Products in Haloform Reactions** **Text:** "Indicate the major organic products from the reaction shown." **Reaction Illustration Explanation:** The image depicts the structure of a ketone with the molecular formula of a methyl ketone (acetone) on the left side. The ketone features a carbonyl group (C=O) with an adjacent trimethyl-methane group (tert-butyl group). An arrow points to the right indicating a chemical reaction, with the following reagents written above it: - **NaOH:** Sodium hydroxide, a strong base. - **Br₂ (excess):** Bromine, indicated to be in excess. This reaction involves the transformation of the given methyl ketone in the presence of sodium hydroxide and an excess of bromine, suggesting a haloform reaction. This scenario typically results in the formation of a carboxylate ion, derived from the original ketone, and a haloform molecule (in this case, bromoform). **Discussion:** The reaction depicted represents a classic example of a haloform reaction, where a methyl ketone is subjected to halogenation followed by basic hydrolysis. This leads to the cleavage of the carbon-carbon bond adjacent to the carbonyl, forming two major products: 1. **Carboxylate Ion (Salt):** The acetyl group (part of the original ketone) gets converted into a carboxylate ion. 2. **Bromoform (CHBr₃):** Formed due to the action of excess bromine on the methyl group. This reaction is commonly used in organic synthesis for the identification and transformation of methyl ketones.
Transcribed Image Text:**Transcription for Educational Website:** **Title: Determining Major Organic Products in Haloform Reactions** **Text:** "Indicate the major organic products from the reaction shown." **Reaction Illustration Explanation:** The image depicts the structure of a ketone with the molecular formula of a methyl ketone (acetone) on the left side. The ketone features a carbonyl group (C=O) with an adjacent trimethyl-methane group (tert-butyl group). An arrow points to the right indicating a chemical reaction, with the following reagents written above it: - **NaOH:** Sodium hydroxide, a strong base. - **Br₂ (excess):** Bromine, indicated to be in excess. This reaction involves the transformation of the given methyl ketone in the presence of sodium hydroxide and an excess of bromine, suggesting a haloform reaction. This scenario typically results in the formation of a carboxylate ion, derived from the original ketone, and a haloform molecule (in this case, bromoform). **Discussion:** The reaction depicted represents a classic example of a haloform reaction, where a methyl ketone is subjected to halogenation followed by basic hydrolysis. This leads to the cleavage of the carbon-carbon bond adjacent to the carbonyl, forming two major products: 1. **Carboxylate Ion (Salt):** The acetyl group (part of the original ketone) gets converted into a carboxylate ion. 2. **Bromoform (CHBr₃):** Formed due to the action of excess bromine on the methyl group. This reaction is commonly used in organic synthesis for the identification and transformation of methyl ketones.
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