Indicate the major organic product from the reaction shown. 1. LDA, -78°C 2. Br

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Question 6

**Question:**

Indicate the major organic product from the reaction shown.

**Reaction Details:**

- Reactant: Cyclohexanone
- Reagents and conditions:
  1. LDA, -78°C
  2. Ethyl bromide (Br)

**Explanation:**

1. **Reagent 1: LDA (Lithium Diisopropylamide)**
   - LDA is a strong, non-nucleophilic base. At -78°C, it deprotonates the most accessible alpha-hydrogen of the cyclohexanone, leading to the formation of an enolate ion. This enolate is then in a state to attack an electrophile.

2. **Reagent 2: Ethyl Bromide (Br)**
   - The enolate formed reacts with ethyl bromide, resulting in an alkylation reaction. The ethyl group is added to the carbon atom that was deprotonated.

**Overall Reaction:**

The result of this reaction is an alpha-ethyl cyclohexanone, where an ethyl group (CH2CH3) is added to the alpha position next to the carbonyl group of cyclohexanone. This reaction is a typical example of enolate alkylation.
Transcribed Image Text:**Question:** Indicate the major organic product from the reaction shown. **Reaction Details:** - Reactant: Cyclohexanone - Reagents and conditions: 1. LDA, -78°C 2. Ethyl bromide (Br) **Explanation:** 1. **Reagent 1: LDA (Lithium Diisopropylamide)** - LDA is a strong, non-nucleophilic base. At -78°C, it deprotonates the most accessible alpha-hydrogen of the cyclohexanone, leading to the formation of an enolate ion. This enolate is then in a state to attack an electrophile. 2. **Reagent 2: Ethyl Bromide (Br)** - The enolate formed reacts with ethyl bromide, resulting in an alkylation reaction. The ethyl group is added to the carbon atom that was deprotonated. **Overall Reaction:** The result of this reaction is an alpha-ethyl cyclohexanone, where an ethyl group (CH2CH3) is added to the alpha position next to the carbonyl group of cyclohexanone. This reaction is a typical example of enolate alkylation.
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