O d. 2.00Independent random sampling from two normally distributed populations gives thefollowing results: n,- 55, x= 520, o, - 30, n,= 45, y- 482, and o,-24.Find the 98% confidence interval for the difference in the means of the two populations.Lütfen birini seçin:O a 1002(+-)12.58Ob.38(+-)12.58c. 38(+-)19 86d. 1002(+)19.86The manufacturer of a new chewing gilm claims that at least 80% of dentists surveyed prefertheir type of gum and recommend it for their patients who chew gum An independentconsumer research firm decides to test their claim The findings in a sample of 200 dentistsindicate that 741% of the respondents do actually prefer their gum Which of the followingStatements IS most accurate?

Independent random sampling from two normally distributed populations gives the following results: n,- 55, x= 520, o, - 30, n, = 45, y- 482, and o,=24. Find the 98% confidence interval for the difference in the means of the two populations. Lütfen birini seçin. a 1002(+-)12.58 b. 38(+-)12.58 Oc 38(+-)19 86 Od 1002(+-)19 86

Independent random sampling from two normally distributed populations gives the following results: n,- 55, x= 520, o, - 30, n, = 45, y- 482, and o,=24. Find the 98% confidence interval for the difference in the means of the two populations. Lütfen birini seçin. a 1002(+-)12.58 b. 38(+-)12.58 Oc 38(+-)19 86 Od 1002(+-)19 86

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

6. A 90% confidence interval for p is given as (0.35,0.65). How large was the sample used to construct this interval?
A random sample of n measurements was selected from a population with unknown mean p and known standard deviation o. Find the margin of error (often denoted as E or EBM) for a 95% confidence interval for u for the given situation. Round to the nearest hundredth when necessary. n = 104, x = 174, o = 11
4. The lower value of a 90% confidence interval for the variance in maze-running times of a sample of 31 rats is 4.62. Based on this, form a 98% confidence interval for 02 Answer: 3.973 to 13.5219
Use the sample information x⎯⎯x¯ = 37, σ = 6, n = 15 to calculate the following confidence intervals for μ assuming the sample is from a normal population.
Answer (1.32, 10.68), (1, 11)
) A random sample of size n = 6 is selected from a normal population, with 12) the sample variance s? = .18. Determine a confidence interval for the population variance o? with a confidence level of 98 percent.
can you answer 26a and b
A random sample of n1n1 = 236 people who live in a city were selected and 90 identified as a "dog person." A random sample of n2n2 = 103 people who live in a rural area were selected and 56 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. ___________< p1−p2p1-p2 <_____________
1- A researcher makes a research about the life time of batteries which have a normal distribution. In order to understand the life time of batteries s/he randomly selected 49 batteries and calculate the sample mean as 48 hours and standard deviation of 5 hours. Construct 90 % confidence interval for the true population mean of life time of batteries.