Independent random samples were selected from two quantitative populations, with sample sizes, means, and variancesgiven below.Population1Sample Size3845Sample Mean9.67.3Sample Variance10.8316.49State the null and alternative hypotheses used to test for a difference in the two population means.О н: (и, - н2) + 0 versus Hа: (и, - и2) %3D 0О на: (и, - и2) %3D 0 versus H,: (и, — и2) > оО на: (и, - и2) %3D 0 versus Hа: (и, — и2) + 0О н: (и, — и,) %3D 0 versus H,: (и, — и) < 0О Hо: (и1 — н2) <0 versus Hа: (И1 — и2) > оCalculate the necessary test statistic. (Round your answer to two decimal places.)z =2.77Calculate the rejection region with a = 0.01. (Round your answers to two decimal places. If the test is one-tailed, enterNONE for the unused region.)z > 2.77z < 2.77Draw the appropriate conclusion.O H, is not rejected. There is insufficient evidence to indicate a difference in mean.Ho is not rejected. There is sufficient evidence to indicate a difference in mean.O Ho is rejected. There is insufficient evidence to indicate a difference in mean.O Ho is rejected. There is sufficient evidence to indicate a difference in mean.

Solution-: Given: n_1=38, \bar{x_1}=9.6, \sigma_1^2=10.83 , n_2=45, \bar{x_2}=7.3,\sigma_2…

Answered: Independent random samples were…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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