Independent random samples, each containing 500 observations, were selected from two binomial populations. The samples from populations 1 and 2 produced 444 and 287 successes, respectively. (a) Test Ho : (P1 – P2) = 0 against Ha : (Pi – P2) + 0. Use a = 0.09 test statistic rejection region |2| > The final conclustion is A. We can reject the null hypothesis that (p1 – P2) = 0 and accept that (Pi – P2) + 0. OB. There is not sufficient evidence to reject the null hypothesis that (p1 – P2) = 0. %3D (b) Test Ho : (P1 – P2) = 0 against H. : (Pi – P2) > 0. Use a = 0.08 test statistic = rejection region z > The final conclustion is OA. We can reject the null hypothesis that (p1 – P2) = 0 and accept that (P1 – P2) > 0. B. There is not sufficient evidence to reject the null hypothesis that (p1 – P2) = 0.

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Independent random samples, each containing 500 observations, were selected
from two binomial populations. The samples from populations 1 and 2 produced 444 and
287 successes, respectively.
(a) Test Ho : (P1 - P2) = 0 against Ha : (Pı – P2) + 0. Use a = 0.09
test statistic
rejection region |z| >
The final conclustion is
OA. We can reject the null hypothesis that (P1 – P2) = 0 and accept that
(P1 – P2) + 0.
B. There is not sufficient evidence to reject the null hypothesis that (P1 – P2) = 0.
|
(b) Test Ho : (P1 – P2) = 0 against Ha : (p1 – P2) > 0. Use a =
0.08
test statistic
rejection region z >
The final conclustion is
OA. We can reject the null hypothesis that (p1 – P2) = 0 and accept that
(P — Р) > 0.
B. There is not sufficient evidence to reject the null hypothesis that (p1 – P2) = 0.
Transcribed Image Text:Independent random samples, each containing 500 observations, were selected from two binomial populations. The samples from populations 1 and 2 produced 444 and 287 successes, respectively. (a) Test Ho : (P1 - P2) = 0 against Ha : (Pı – P2) + 0. Use a = 0.09 test statistic rejection region |z| > The final conclustion is OA. We can reject the null hypothesis that (P1 – P2) = 0 and accept that (P1 – P2) + 0. B. There is not sufficient evidence to reject the null hypothesis that (P1 – P2) = 0. | (b) Test Ho : (P1 – P2) = 0 against Ha : (p1 – P2) > 0. Use a = 0.08 test statistic rejection region z > The final conclustion is OA. We can reject the null hypothesis that (p1 – P2) = 0 and accept that (P — Р) > 0. B. There is not sufficient evidence to reject the null hypothesis that (p1 – P2) = 0.
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