ind the probability P(E) if P(E)= 0.28. he probability P(E) is (Simplify your

MATLAB: An Introduction with Applications
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The image presents a probability problem frequently used in educational settings to illustrate basic principles of probability theory. Here is the transcribed and explained content:

---

**Problem**

Given:
- \(P(E^c)\), the probability of the complement of event \(E\), is 0.28.

Question:
- Find the probability \(P(E)\).

**Solution**

Since the probability of the complement of event \(E\) is given by \(P(E^c) = 0.28\), we use the relationship between an event and its complement:

\[ P(E) + P(E^c) = 1 \]

From this equation, we can solve for \(P(E)\):

\[ P(E) = 1 - P(E^c) = 1 - 0.28 = 0.72 \]

**Conclusion**

The probability \(P(E)\) is 0.72. 

---

This is how the problem should be presented on an educational website, with both the problem and its step-by-step solution provided for clarity.
Transcribed Image Text:The image presents a probability problem frequently used in educational settings to illustrate basic principles of probability theory. Here is the transcribed and explained content: --- **Problem** Given: - \(P(E^c)\), the probability of the complement of event \(E\), is 0.28. Question: - Find the probability \(P(E)\). **Solution** Since the probability of the complement of event \(E\) is given by \(P(E^c) = 0.28\), we use the relationship between an event and its complement: \[ P(E) + P(E^c) = 1 \] From this equation, we can solve for \(P(E)\): \[ P(E) = 1 - P(E^c) = 1 - 0.28 = 0.72 \] **Conclusion** The probability \(P(E)\) is 0.72. --- This is how the problem should be presented on an educational website, with both the problem and its step-by-step solution provided for clarity.
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