incorrect At least one of the answers above is NOT correct. 3 of the questions remain unanswered. It is estimated that 16.6% of all adults in the U.S. are uninsured. You take a random sample of 224 adults seen by a certain clinic and find that 48 are uninsured. Use the normal approximation to the binomial distribution to estimate the probability of randomly selecting 224 adults with 48 or more of them being s or uninsured. (a) Find the mean. 37.18 (b) Find the standard deviation. 2.07 (c) Find the z-score. (d) Find the probability. (e) Is this event unusual? Yes No
incorrect At least one of the answers above is NOT correct. 3 of the questions remain unanswered. It is estimated that 16.6% of all adults in the U.S. are uninsured. You take a random sample of 224 adults seen by a certain clinic and find that 48 are uninsured. Use the normal approximation to the binomial distribution to estimate the probability of randomly selecting 224 adults with 48 or more of them being s or uninsured. (a) Find the mean. 37.18 (b) Find the standard deviation. 2.07 (c) Find the z-score. (d) Find the probability. (e) Is this event unusual? Yes No
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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o the Binomial Distribution: MATH-1300-OLA04
A WeBWork : MATH_1300_OLA04_Fall_2021: Homework 22 : 3
E 83.4% as a Decimal | What is 83.
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incorrect
incorrect
incorrect
At least one of the answers above is NOT correct.
3 of the questions remain unanswered.
It is estimated that 16.6% of all adults in the U.S. are uninsured. You take a random sample of 224 adults seen by a certain clinic and find that 48 are
uninsured.
Use the normal approximation to the binomial distribution to estimate the probability of randomly selecting 224 adults with 48 or more of them being
uninsured.
(a) Find the mean.
37.18
(b) Find the standard deviation.
2.07
(c) Find the z-score.
(d) Find the probability.
(e) Is this event unusual?
Yes
No
Note: You can earn partial credit on this problem.
OCT
tv
12
MacBook Pro
Pert Demal
&
23
3
4.
5
7
8
E
Y
* 00](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1cf6cf2e-526b-4180-bbdb-a6f7567096ab%2F2e8de3e7-e1a4-4956-8d1f-441094ef1d98%2Fcav6dxq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:iew
History
Bookmarks
Window
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A webwork.piedmont.edu
o the Binomial Distribution: MATH-1300-OLA04
A WeBWork : MATH_1300_OLA04_Fall_2021: Homework 22 : 3
E 83.4% as a Decimal | What is 83.
Previous Problem
Problem List
Next Problem
incorrect
incorrect
incorrect
At least one of the answers above is NOT correct.
3 of the questions remain unanswered.
It is estimated that 16.6% of all adults in the U.S. are uninsured. You take a random sample of 224 adults seen by a certain clinic and find that 48 are
uninsured.
Use the normal approximation to the binomial distribution to estimate the probability of randomly selecting 224 adults with 48 or more of them being
uninsured.
(a) Find the mean.
37.18
(b) Find the standard deviation.
2.07
(c) Find the z-score.
(d) Find the probability.
(e) Is this event unusual?
Yes
No
Note: You can earn partial credit on this problem.
OCT
tv
12
MacBook Pro
Pert Demal
&
23
3
4.
5
7
8
E
Y
* 00
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