#include using namespace std; int x = 10; int main () int x = 20; %3D cout << "x is " << x << endl; { int x = 42; %3D cout << "x is " << x << endl; cout << "x is " << ::x << end%3; int x = 30; cout << "x is " << x << endl; cout << "x is " << ::x << endl; cout << "x is " << x << endl;
#include using namespace std; int x = 10; int main () int x = 20; %3D cout << "x is " << x << endl; { int x = 42; %3D cout << "x is " << x << endl; cout << "x is " << ::x << end%3; int x = 30; cout << "x is " << x << endl; cout << "x is " << ::x << endl; cout << "x is " << x << endl;
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
In C++

Transcribed Image Text:**C++ Scope and Storage Class Example**
The following C++ program demonstrates the concepts of storage class and scope:
```cpp
#include <iostream>
using namespace std;
int x = 10;
int main()
{
int x = 20;
cout << "x is " << x << endl;
{
int x = 42;
cout << "x is " << x << endl;
cout << "x is " << ::x << endl;
}
{
int x = 30;
cout << "x is " << x << endl;
cout << "x is " << ::x << endl;
}
cout << "x is " << x << endl;
}
```
**Explanation:**
1. **Global Scope:**
- `int x = 10;` is declared outside all functions, making it a global variable accessible throughout the entire program using the scope resolution operator `::`.
2. **Main Function Scope:**
- Within `main()`, `int x = 20;` declares a local variable `x` that shadows the global variable `x`.
3. **Block Scopes:**
- The first inner block declares `int x = 42;`. Here, `cout << "x is " << x << endl;` prints the local `x` (42), while `cout << "x is " << ::x << endl;` prints the global `x` (10).
- The second block similarly declares `int x = 30;`. The first print statement outputs 30, while the second outputs the global `x` (10).
4. **End of Main Function:**
- Finally, `cout << "x is " << x << endl;` outputs the `x` from the main function's scope (20).
Understanding how scope works in C++ is crucial for effectively utilizing variables and avoiding potential naming conflicts.
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