#include "stdafx.h" #include #include #include in c++ How do I list all of the price entered. for example, if the customer says yes three times. How do I list all three? below is an example const float discount = .80; double cost; double Price; char ans; do { cout << "\n\nPlease enter the cost to replace your building: "; cin >> cost; price = cost * discount;//calculate the insurance cout << "Hello, " << name << " The price is << fixed << setprecision(2) << price << endl; cout << "\nWould you like to input another? (Y/N): ";//prompts user to enter another insurance cin >> answ; } while (answ == 'Y' || answ == 'y');
#include "stdafx.h" #include #include #include in c++ How do I list all of the price entered. for example, if the customer says yes three times. How do I list all three? below is an example const float discount = .80; double cost; double Price; char ans; do { cout << "\n\nPlease enter the cost to replace your building: "; cin >> cost; price = cost * discount;//calculate the insurance cout << "Hello, " << name << " The price is << fixed << setprecision(2) << price << endl; cout << "\nWould you like to input another? (Y/N): ";//prompts user to enter another insurance cin >> answ; } while (answ == 'Y' || answ == 'y');
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
#include "stdafx.h"
#include<iostream>
#include<string>
#include <iomanip>
in c++
How do I list all of the price entered. for example, if the customer says yes three times. How do I list all three? below is an example
const float discount = .80;
double cost;
double Price;
char ans;
do
{
cout << "\n\nPlease enter the cost to replace your building: ";
cin >> cost;
price = cost * discount;//calculate the insurance
cout << "Hello, " << name << " The price is << fixed << setprecision(2) << price << endl;
cout << "\nWould you like to input another? (Y/N): ";//prompts user to enter another insurance
cin >> answ;
} while (answ == 'Y' || answ == 'y');
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