#include #include using namespace std; // ADD CODE: Add prototypes for the unmix and decipher functions here int main() { string code "K*@*R*S* \@37*D*W*D*Q*B*H*R*D* "; cout << "step e: " << code << endl; string unmixed; unmixed = unmix(code); cout << "Step 1: " << unmixed << endl; decipher (unmixed); cout << "Step 2: " << unmixed << endl; return e; =//Function unmix: // Returns a new string containing // only the even characters of string s string unmix(string s) { string ret; for (int i e; i < s.length(); i++) { //ADD CODE: if i is even { //COMPLETE LINE: add the character at i onto ret ret += return ret; =//Function decipher: // Implements a Caesar Cipher decoder // every character in s will have 1 added on to its value Evoid decipher(string& s) { //ADD CODE: write a for loop to that counts i from e to the length of string s s[i] = s[i] + 13;

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Complete the program by following the comment in the coda. C++ language
D#include <iostream>
#include <string>
using namespace std;
//ADD CODE: Add prototypes for the unmix and decipher functions here
aint main()
string code = "K*@*R*S*\037*D*W*D*Q*B*H*R*D* ";
cout << "Step 0:
<< code << endl;
string unmixed;
unmixed = unmix(code);
cout << "Step 1: " << unmixed << endl;
decipher (unmixed);
cout << "Step 2:
<< unmixed << endl;
return e;
a//Function unmix:
// Returns a new string containing
// only the even characters of string s
astring unmix(string s)
{
string ret;
for (int i = 0; i < s.length(); i++)
{
//ADD CODE: if i is even
{
//COMPLETE LINE: add the character at i onto ret
ret +=
}
return ret;
e//Function decipher:
// Implements a Caesar Cipher decoder
|// every character in s will have 1 added on to its value
avoid decipher(string& s)
{
//ADD CODE: write a for loop to that counts i from e to the length of string s
s[i] = s[i] + 1;
Transcribed Image Text:D#include <iostream> #include <string> using namespace std; //ADD CODE: Add prototypes for the unmix and decipher functions here aint main() string code = "K*@*R*S*\037*D*W*D*Q*B*H*R*D* "; cout << "Step 0: << code << endl; string unmixed; unmixed = unmix(code); cout << "Step 1: " << unmixed << endl; decipher (unmixed); cout << "Step 2: << unmixed << endl; return e; a//Function unmix: // Returns a new string containing // only the even characters of string s astring unmix(string s) { string ret; for (int i = 0; i < s.length(); i++) { //ADD CODE: if i is even { //COMPLETE LINE: add the character at i onto ret ret += } return ret; e//Function decipher: // Implements a Caesar Cipher decoder |// every character in s will have 1 added on to its value avoid decipher(string& s) { //ADD CODE: write a for loop to that counts i from e to the length of string s s[i] = s[i] + 1;
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