include #include int main() { fork(); pause(
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Explain how many times “hello” will be printed for the following UNIX code :
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main() {
fork();
pause();
fork();
printf(“hello\n”);
return 0 ; }
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- Please run this on linux, compile and look at the placement for row "Tangent". Match the numbers below tangent and make sure all the other row numbers are lining up with the other headings main.c #include <stdio.h>#include <math.h> #define M_PI 3.14159265358979323846 /** * Given a incrementVal value, this function will print a table of trigonometric values * from 0 to 360, in increments of the incrementVal value. * For example, if the incrementVal value is 90, the table will print values for 0, 90, 180, 270 and 360. * incrementVal - the degree value to use for the increment*/void displayTriTab(int incrementVal) { //Display the header for the table printf("\n\t--- TRIGONOMETRIC TABLE ---\n\n"); // Display the column headings for the table printf("%3s%10s%10s%10s%10s\n", "Degrees", "Radians", "sine", "cosine", "tangent"); printf("%3s%10s%10s%10s%10s\n", "-------", "-------", "------", "-------", "-------"); //Declare variables for radians, sine cosine,…I've been asking about this poker game that I have been trying to compile in c++. Main.cpp #include <iostream>#include <string>#include <fstream>#include <iomanip>#include <sstream>#include "card.h"#include "deck.h"#include "hand.h"using namespace std;int main(){string repeat = "Y";Deck myDeck;Hand myHand;string exchangeCards;while (repeat == "Y" || repeat == "y"){cout << endl;myHand.newHand(myDeck);myHand.print();cout << endl;cout << "Would you like to exchange any cards? [Y / N]: ";getline(cin, exchangeCards);while (exchangeCards != "Y" && exchangeCards != "y" && exchangeCards != "X" && exchangeCards != "n"){cout << "Please enter Y or N only: ";getline(cin, exchangeCards);}if(exchangeCards == "Y" || exchangeCards == "y"){myHand.exchangeCards(myDeck);}cout << endl;myHand.print();cout << endl;myDeck.reset(); // Resets the deck for a new gamecout << "Play again? [Y / N]: ";getline(cin,…#include <iostream> #include <cmath> using namespace std; // declare functions void display_menu(); void convert_temp(); double to_celsius(double fahrenheit); double to_fahrenheit(double celsius); int main() { cout << "Convert Temperatures\n\n"; display_menu(); char again = 'y'; while (again == 'y') { convert_temp(); cout << "Convert another temperature? (y/n): "; cin >> again; cout << endl; } cout << "Bye!\n"; } // define functions void display_menu() { cout << "MENU\n" << "1. Fahrenheit to Celsius\n" << "2. Celsius to Fahrenheit\n\n"; } void convert_temp() { int option; cout << "Enter a menu option: "; cin >> option; double f = 0.0; double c = 0.0; switch (option) { case 1: cout << "Enter degrees Fahrenheit: "; cin >> f; c =…
- Convert from C to C++ .Thank you. / include all required libraries#include<stdio.h>#include<stdlib.h>#include<sys/types.h>#include<sys/wait.h>#include<unistd.h> // variable to store number of generationsint num_generations; // function to print the generationsvoid printGeneration(int n){// stop if number of generations are reachedif(n>num_generations)return; // create a forkpid_t p = fork(); // generate new generationsif(p==0)printGeneration(n+1);else if(p>0)wait(0); // wait until child process terminates // print the present generationif(p!=0){// if n is 0if(n==0)printf("Parent. "); // print parent// if n is 1else if(n==1)printf("Child. "); // print child// for all other caseselse{// print grandchildrenfor(int i=0;i<n-2;i++)printf("Great ");printf("Grandchild. ");}// print pid and ppidprintf("pid: %d ppid: %d\n",getpid(),getppid());}} // main functionint main(int argc, char* argv[]){// if no arguments are providedif(argc==1){// print…Use the following code to perform the following tasks: Show all variables that are visible at POSITION #1 only. Provide their nesting level and offset, using the activation record layout discussed in class.S2how the contents of the call stack at the time when control reaches POSITION #1. Use the layout defined in chapter 10 and used in class for statically scoped languages that allow nested functions. Show values and links. function main() {int w = 1, x = 2; function a(bool flag) {int x = 3; function b() { c(4); } function c(int x) {// POSITION #1 } b(); } a(true); } Provide a leftmost derivation for the string aaabb using the following grammar:<S> → <A><B> <A> → a<A> | a <B> → b<B> | b Identify the shortest possible legal program: <program> → program <ident> ( <ident> { , <ident> } ) <block> <ident> → A | B<block> → begin <stmts> end <stmts> → <ident> = <ident> |…In C++: Examine the code segment. What will be printed? If there are any errors indicate the nature of each error. int a[7] = {31, 12, 32, 14, 25, 16, 27}; int *ptr; ptr = & a[2]; for ( i=1; i<=5; i=i+2) cout << *(ptr +i); cout << a[0] << *ptr << *ptr - 2 << *(ptr -1)) << endl;
- Given the following program, please determine how many times the word “hello” is printed out. Assume that fork() is always successful. [1 pt] #include <sys/types.h> #include <stdio.h> int main() { pid_t a, b; a = fork(); b = fork(); if (a == 0) b = fork(); if (b == 0) a = fork(); printf(“hello\n”); return 0; }Simple try-catch Program This lab is a simple program that demonstrates how try-catch works. You will notice the output when you enter incorrect input (for example, enter a string or double instead of an integer). Type up the code, execute and submit the results ONLY. Do at least 2 valid inputs and 1 invalid. NOTE: The program does not stop executing after it encounters an error! CODE: import java.util.Scanner; public class TryCatch Example Simple { public static void main(String[] args) { Scanner input = new Scanner(System.in); int num = 0; System.out.println("Even number tester.\n"); System.out.println("Enter your name: "); String name = input.nextLine(); while (true) { try { System.out.println("Enter an integer : ");#include <stdio.h>#include <stdlib.h>#include <unistd.h>#include <sys/types.h>#include <sys/wait.h> int main(){ int i, s; int a[] = {23,4,8,33,25,7,12,6,49,50,11,20,21,24,35}; pid_t pid; pid = fork(); if (pid == 0) { printf("I'm a child, I'll be printing the even numbers:\n"); for(i=0;i<(sizeof(a)/sizeof(int));i++) if(a[i]%2 == 0) printf("%d ",a[i]); } else { printf("I'm the parent, I'll be printing the odd numbers:\n"); if (pid > 0) pid = waitpid(pid, &s, 0); for(i=0;i<(sizeof(a)/sizeof(int));i++) if(a[i]%2 != 0) printf("%d ",a[i]); } return 0;} the output seem to have some error whereby it cannot output the number for the first if
- Convert Code Into Python and Eliminate Syntax errors: #include<iostream>#include<fstream>#include<math.h>#include<iomanip>using namespace std;int main(){ //declare input and output file sterams ifstream inFile; ofstream outFile; //declare required variables double roughness[50], min, max, sum=0, sqSum=0; double Ra, Rq, maxRoughness; int i = 0; //open input file inFile.open("Surface.txt"); //check input file exist or not if(!inFile) //display error message cout<<"Error in opening the file..."<<endl; else { //read the first value from file inFile>>roughness[i]; //initialise min and max values min = max = roughness[i]; //initialise sum sum+=roughness[i]; //initialise sqSum sqSum+=roughness[i]*roughness[i]; //loop till end of file while(!inFile.eof()) { i++; //read value from file; one at a time…In Python IDLE Will the following code run? Why or why not? Assume that the blocks of code are correctly formed and will run if correctly called and that this is the entire program. def fct(): block1 def main(): block2 fct() block3