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#include #define NAME_LEN 100 struct part{ int number; char name [NAME_LEN+1]; int on hand; }; struct part build_part(int number, char *name, int on_hand) { struct part p; p.number = number; strcpy(p.name, name); p.on_hand = on_hand; return p; } int main() { struct part pl = build_part(10, "Memory", 4); } in the code above: a copy of the contents of p is assigned to p1. the location of p is assigned to p1. p1 will not have a meaningful value, as the contents of p cannot be accessed outside the function build_part. the strcpy call will not work, as name and p.name have different types.

#include #define NAME_LEN 100 struct part{ int number; char name [NAME_LEN+1]; int on hand; }; struct part build_part(int number, char *name, int on_hand) { struct part p; p.number = number; strcpy(p.name, name); p.on_hand = on_hand; return p; } int main() { struct part pl = build_part(10, "Memory", 4); } in the code above: a copy of the contents of p is assigned to p1. the location of p is assigned to p1. p1 will not have a meaningful value, as the contents of p cannot be accessed outside the function build_part. the strcpy call will not work, as name and p.name have different types.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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#include <string.h> #define NAME_LEN 100 struct part{ int number; char name [NAME_LEN+1]; int on_hand; }; struct part build_part(int number, char *name, int on_hand) { struct part p; p.number = number; strcpy(p.name, name); on_hand; p.on_hand return p; } int main() { } = struct part pl In the code above: = build_part(10, "Memory", 4); a copy of the contents of p is assigned to p1. the location of p is assigned to p1. Op1 will not have a meaningful value, as the contents of p cannot be accessed outside the function build_part. the strcpy call will not work, as name and p.name have different types.
Transcribed Image Text:#include <string.h> #define NAME_LEN 100 struct part{ int number; char name [NAME_LEN+1]; int on_hand; }; struct part build_part(int number, char *name, int on_hand) { struct part p; p.number = number; strcpy(p.name, name); on_hand; p.on_hand return p; } int main() { } = struct part pl In the code above: = build_part(10, "Memory", 4); a copy of the contents of p is assigned to p1. the location of p is assigned to p1. Op1 will not have a meaningful value, as the contents of p cannot be accessed outside the function build_part. the strcpy call will not work, as name and p.name have different types.
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