In2 1/1 = k For a first order process, successive half-lives are equal amounts of time, since which is a constant for a given reaction at a given temperature. In other words, half-life for a reaction of 1st order is independent on the initial concentration. As shown in the data below: [NOCI] (mol/L) 2.000 1.000 0.5000 0.2500 0.1250 0.0625 time ( min ) 0.00 2.00 4.00 6.00 8.00 10.0 It takes 2.00 minutes to reduce [NOCI] from 2.000mol/L to 1.000mol/L. It takes the same amount of time (2.00 minutes) to reduce [NOCI] from 1.000mol/L to 0.5000mol/L and the list goes on. If you are given a data as above, you should be able to tell right away that the reaction is 1st order. What can we say about successive half-lives for zero and 2nd order processes? Show how you arrived at your answer. (hint: derive the half-life equation for the zero and 2nd order reactions and use the half-life equations to support your answers.)

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Chapter1: Chemical Foundations
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In2
k
For a first order process, successive half-lives are equal amounts of time, since
which is a constant for a given reaction at a given temperature. In other words,
half-life for a reaction of 1st order is independent on the initial concentration. As shown in
the data below:
[NOCI] (mol/L)
2.000
1.000
0.5000
0.2500
0.1250
0.0625
time ( min )
0.00
2.00
4.00
6.00
8.00
10.0
It takes 2.00 minutes to reduce [NOCI] from 2.000mol/L to 1.000mol/L. It takes the
same amount of time (2.00 minutes) to reduce [NOCI] from 1.000mol/L to
0.5000mol/L and the list goes on. If you are given a data as above, you should be
able to tell right away that the reaction is 1st order.
What can we say about successive half-lives for zero and 2nd order processes? Show how
you arrived at your answer. (hint: derive the half-life equation for the zero and 2nd order
reactions and use the half-life equations to support your answers.)
Transcribed Image Text:In2 k For a first order process, successive half-lives are equal amounts of time, since which is a constant for a given reaction at a given temperature. In other words, half-life for a reaction of 1st order is independent on the initial concentration. As shown in the data below: [NOCI] (mol/L) 2.000 1.000 0.5000 0.2500 0.1250 0.0625 time ( min ) 0.00 2.00 4.00 6.00 8.00 10.0 It takes 2.00 minutes to reduce [NOCI] from 2.000mol/L to 1.000mol/L. It takes the same amount of time (2.00 minutes) to reduce [NOCI] from 1.000mol/L to 0.5000mol/L and the list goes on. If you are given a data as above, you should be able to tell right away that the reaction is 1st order. What can we say about successive half-lives for zero and 2nd order processes? Show how you arrived at your answer. (hint: derive the half-life equation for the zero and 2nd order reactions and use the half-life equations to support your answers.)
Expert Solution
Step 1: Defining order of reaction

Answer:

Power of concentration term of a reactant in rate law is called as order of reaction with respect to that reactant and sum of the powers of all concentration terms is equal to the overall order of reaction.

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