3. It was believed that implementing strict measures is key in reducing the spread of a newvirus. A random selection of 50 regions with relaxed measures and 55 regions with strictmeasures were surveyed how many cases they have. It was found that among regions withrelaxed measures, the average number of cases per million is 50,000 with standard deviationof 35,000. Among regions with strict measures, the average number of cases per million is60,000 with standard deviation of 30,000. Using 5% level of significance, conduct ahypothesis test to determine if strict measures is effective in reducing cases in regions withlower standards of living.In words, define the random variable X1 =b. Нос. На:d. The level of significance ise. Determine the test statistic using the data (show solution).f. Provide the decision rule of the test.g. Decision:h. Write a clear conclusion using the format:i. sufficient evidence to reject the null hypothesis thabettingа.and X2 =Activate V at < _% level of significance>.

Using 5% level of significance, we need to conduct a hypothesis test to determine if strict measures…

Answered: In words, define the random variable X,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A student performs a test of Ho: u = 100 versus H,: > 100 and gets a P-value of 0.044. The student says, "There is a 0.044 probability of getting the sample result I did by chance alone." What did the student do wrong in their explanation? The student forgot to include the condition and the direction in their interpretation. The student forgot to state the conditional probability. The student forgot to make a decision about the null hypothesis. The student forgot to include a directional range of values. O The student did nothing wrong. The interpretation is fine.
Assume that a simple random sample has been selected from a normally distributed population. Identify the null hypothesis, alternative hypothesis, test statistic, P-value (or range of p-values), conclusion about the null hypothesis, and final conclusion that addresses the original claim. 1) Test the claim that the mean age of the graduate school population in one city is less than 33 years. Sample data are summarized as n 67, x = 42.4 years, and s = 31.5 years. Use a significance level of a = 0.10.
Solve and show work.
WHO (World Health Organization) states that 1500 cals is the average daily calorie intake for the people in Hatay. A group of 100 people are selected from there, and the mean and standard deviation of the daily calorie intake are found to be 1705 cals and 900 cals, respectively. Use 5% significance level and;a) Perform a test of hypothesis if the WHO statement about the daily average calorie intake still holds?b) Find the probability of committing a Type II error and calculate the Power of Test when the real average is 1805.
lume Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. A safety administration conducted crash tests of child booster seats for cars. Listed below are results from those tests, with the measurements given in hic (standard head injury condition units). The safety requirement is that the hic measurement should be less than 1000 hic. Use a 0.05 significance level to test the claim that the sample is from a population with a mean less than 1000 hic, Do the results suggest that all of the child booster seats meet the specified requirement? 712 660 1192 616 588 534 O What are the hypotheses?
Consider a sample of 48 football games, where 32 of them were won by the home team. Use a 0.10 significance level to test the claim that the probability that the home team wins is greater than one-half. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p>0.5 H,:p= 0.5 О В. Но: р30.5 H1: p#0.5 О с. Но: р30.5 H1:p>0.5 O D. Ho: p=0.5 H1:p<0.5 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.)
IDENTIFY IF IT IS| ONE-TAILED LEET TEST, ONE-TAILED RIGHT, NONE-TAILED, TWO-TAILED Given: n = 8 H.:µ = 30 x = 27 s = 3 HaiH 208 H = 208 3.
Test the claim that the mean GPA of night students is larger than 2 at the 0.005 significance level. The null and alternative hypothesis would be: Но:р 2 Нo:д 0.5 Но:и — 2 Нi:р> 0.5 H:n 2 Hi:p#0.5 Hі:р<0.5 Hі:р +2 The test is: two-tailed left-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 2.02 with a standard deviation of 0.08 The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis O Reject the null hypothesis
Consider a sample of 49 football games, where 33 of them were won by the home team. Use a 0.01 significance level to test the claim that the probability that the home team wins is greater than one-half. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p>0.5 H1:p=0.5 ов. Но: р-0.5 H;:p0.5 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Fail to reject Ho. There is sufficient evidence to support the claim that the probability of the home team winning is greater than one-half. O B. Reject Ho. There is sufficient evidence to support the claim that the probability of the home team winning is greater than one-half. OC. Fail to reject Ho. There is not sufficient…
Suppose that in a random selection of 100 colored candies, 23% of them are blue. The candy company claims that the percentage of blue candies is equal to 28%. Use a 0.10 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p= 0.28 H:p0.28 О С. Но: р-0.28 H,: p#0.28 O D. Ho: p#0.28 H,:p=0.28
aanswer: please

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