In which reaction does the oxidation number of oxygen increase? A) Mgo (s) + H2O (I) → Mg(OH)2 (s) B 2502 (g) + 02 (g) 2S03 (g) C) 2H20 () → 2H2 (g) + 02 (g) D HCI (aq) + NaOH (aq) → NaCI (aq) + H20 () E) Ba(NO3)2 (aq) + K2SO4 (aq) BaSO4 (s) + 2KNO3 (aq)

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Chapter1: Chemical Foundations
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**Question:**

In which reaction does the oxidation number of oxygen increase?

**Options:**

**A.** \( \text{MgO (s)} + \text{H}_2\text{O (l)} \rightarrow \text{Mg(OH)}_2 \text{ (s)} \)

**B.** \( 2\text{SO}_2 \text{ (g)} + \text{O}_2 \text{ (g)} \rightarrow 2\text{SO}_3 \text{ (g)} \)

**C.** \( 2\text{H}_2\text{O (l)} \rightarrow 2\text{H}_2 \text{ (g)} + \text{O}_2 \text{ (g)} \)

**D.** \( \text{HCl (aq)} + \text{NaOH (aq)} \rightarrow \text{NaCl (aq)} + \text{H}_2\text{O (l)} \)

**E.** \( \text{Ba(NO}_3\text{)}_2 \text{ (aq)} + \text{K}_2\text{SO}_4 \text{ (aq)} \rightarrow \text{BaSO}_4 \text{ (s)} + 2\text{KNO}_3 \text{ (aq)} \)

**Explanation of Correct Option:**

In this question, you need to determine which reaction involves an increase in the oxidation number of oxygen. Consider the following:

- Option **A** involves the reaction of magnesium oxide with water, forming magnesium hydroxide. Here, the oxidation state of oxygen does not change.
  
- Option **B** involves the reaction of sulfur dioxide with oxygen to form sulfur trioxide. The oxidation number of oxygen remains unchanged.

- Option **C** involves the decomposition of water into hydrogen and oxygen gas. In this reaction, the oxygen molecules are formed from water, where each oxygen is initially assigned an oxidation state of -2. In \( \text{O}_2 \), the oxidation state of oxygen is 0, indicating an increase.

- Option **D** describes a neutralization reaction between hydrochloric acid and sodium hydroxide, which does not change the oxidation state of oxygen.

- Option **E** describes a double displacement reaction between barium nitrate and potassium sulfate, which involves no change in the oxidation states of any
Transcribed Image Text:**Question:** In which reaction does the oxidation number of oxygen increase? **Options:** **A.** \( \text{MgO (s)} + \text{H}_2\text{O (l)} \rightarrow \text{Mg(OH)}_2 \text{ (s)} \) **B.** \( 2\text{SO}_2 \text{ (g)} + \text{O}_2 \text{ (g)} \rightarrow 2\text{SO}_3 \text{ (g)} \) **C.** \( 2\text{H}_2\text{O (l)} \rightarrow 2\text{H}_2 \text{ (g)} + \text{O}_2 \text{ (g)} \) **D.** \( \text{HCl (aq)} + \text{NaOH (aq)} \rightarrow \text{NaCl (aq)} + \text{H}_2\text{O (l)} \) **E.** \( \text{Ba(NO}_3\text{)}_2 \text{ (aq)} + \text{K}_2\text{SO}_4 \text{ (aq)} \rightarrow \text{BaSO}_4 \text{ (s)} + 2\text{KNO}_3 \text{ (aq)} \) **Explanation of Correct Option:** In this question, you need to determine which reaction involves an increase in the oxidation number of oxygen. Consider the following: - Option **A** involves the reaction of magnesium oxide with water, forming magnesium hydroxide. Here, the oxidation state of oxygen does not change. - Option **B** involves the reaction of sulfur dioxide with oxygen to form sulfur trioxide. The oxidation number of oxygen remains unchanged. - Option **C** involves the decomposition of water into hydrogen and oxygen gas. In this reaction, the oxygen molecules are formed from water, where each oxygen is initially assigned an oxidation state of -2. In \( \text{O}_2 \), the oxidation state of oxygen is 0, indicating an increase. - Option **D** describes a neutralization reaction between hydrochloric acid and sodium hydroxide, which does not change the oxidation state of oxygen. - Option **E** describes a double displacement reaction between barium nitrate and potassium sulfate, which involves no change in the oxidation states of any
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