In which of the following declarations can the identifier x be used as a pointer to a char? (choose all that are true) char *x; char x; O char x[10]; none of the others O char[] = "mystring";

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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**Question:**

In which of the following declarations can the identifier x be used as a pointer to a char? (choose all that are true)

1. [x] char *x;

2. [ ] char x;

3. [ ] char x[10];

4. [ ] none of the others

5. [ ] char[] = "mystring";

**Explanation:**

- **Option 1: char *x;**  
  This declaration is correct for using `x` as a pointer to a `char`. The asterisk (*) indicates that `x` is a pointer.

- **Option 2: char x;**  
  This declares `x` as a character, not a pointer.

- **Option 3: char x[10];**  
  This declares `x` as an array of 10 characters, not a pointer. Although the name of the array can sometimes be used like a pointer, it is fundamentally an array type.

- **Option 4: none of the others**  
  This option is not applicable because one of the declarations does indeed allow for `x` to be a pointer to a char.

- **Option 5: char[] = "mystring";**  
  This syntax is incorrect for declaring a pointer or an array; it's incomplete for either purpose.
Transcribed Image Text:**Question:** In which of the following declarations can the identifier x be used as a pointer to a char? (choose all that are true) 1. [x] char *x; 2. [ ] char x; 3. [ ] char x[10]; 4. [ ] none of the others 5. [ ] char[] = "mystring"; **Explanation:** - **Option 1: char *x;** This declaration is correct for using `x` as a pointer to a `char`. The asterisk (*) indicates that `x` is a pointer. - **Option 2: char x;** This declares `x` as a character, not a pointer. - **Option 3: char x[10];** This declares `x` as an array of 10 characters, not a pointer. Although the name of the array can sometimes be used like a pointer, it is fundamentally an array type. - **Option 4: none of the others** This option is not applicable because one of the declarations does indeed allow for `x` to be a pointer to a char. - **Option 5: char[] = "mystring";** This syntax is incorrect for declaring a pointer or an array; it's incomplete for either purpose.
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