College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![**Question:**
In which circuit would ammeter A show the greatest current?
**Diagrams:**
1. **Circuit (1)**:
- A series circuit with a 1.5V battery.
- There are two resistors each of 5Ω connected in series.
- An ammeter (A) is placed in series with the battery and the resistors.
2. **Circuit (2)**:
- A simple circuit with a 1.5V battery.
- A single 5Ω resistor is connected in series with the battery.
- An ammeter (A) is placed in series with the battery and the resistor.
3. **Circuit (3)**:
- A parallel circuit with a 1.5V battery.
- Two 5Ω resistors are connected in parallel.
- An ammeter (A) is placed in series with the battery and the parallel resistors.
4. **Circuit (4)**:
- A parallel circuit with a 1.5V battery.
- Three 5Ω resistors are connected in parallel.
- An ammeter (A) is placed in series with the battery and the resistors.
**Options:**
- 1
- 2
- 3
- 4
_Select the number corresponding to the circuit where the ammeter reads the greatest current._
**Explanation of Diagrams:**
- **Series Circuits:** In series circuits, the total resistance is the sum of all resistances.
- **Parallel Circuits:** In parallel circuits, the total resistance is reduced and can be calculated using the formula: \( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n} \)
**Analysis:**
- In Circuit (1), the total resistance is \( R_{total} = 5Ω + 5Ω = 10Ω \).
- In Circuit (2), the total resistance is \( R_{total} = 5Ω \).
- In Circuit (3), the total resistance is calculated as \( \frac{1}{R_{total}} = \frac{1}{5Ω} + \frac{1}{5Ω} = \frac{2}{5Ω} \Rightarrow R_{total} = 2.5Ω](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2979df-2aee-456c-8524-93187fc3ab50%2F36bd65c0-8e18-4a1d-b206-abab90216ce6%2F16py61a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
In which circuit would ammeter A show the greatest current?
**Diagrams:**
1. **Circuit (1)**:
- A series circuit with a 1.5V battery.
- There are two resistors each of 5Ω connected in series.
- An ammeter (A) is placed in series with the battery and the resistors.
2. **Circuit (2)**:
- A simple circuit with a 1.5V battery.
- A single 5Ω resistor is connected in series with the battery.
- An ammeter (A) is placed in series with the battery and the resistor.
3. **Circuit (3)**:
- A parallel circuit with a 1.5V battery.
- Two 5Ω resistors are connected in parallel.
- An ammeter (A) is placed in series with the battery and the parallel resistors.
4. **Circuit (4)**:
- A parallel circuit with a 1.5V battery.
- Three 5Ω resistors are connected in parallel.
- An ammeter (A) is placed in series with the battery and the resistors.
**Options:**
- 1
- 2
- 3
- 4
_Select the number corresponding to the circuit where the ammeter reads the greatest current._
**Explanation of Diagrams:**
- **Series Circuits:** In series circuits, the total resistance is the sum of all resistances.
- **Parallel Circuits:** In parallel circuits, the total resistance is reduced and can be calculated using the formula: \( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n} \)
**Analysis:**
- In Circuit (1), the total resistance is \( R_{total} = 5Ω + 5Ω = 10Ω \).
- In Circuit (2), the total resistance is \( R_{total} = 5Ω \).
- In Circuit (3), the total resistance is calculated as \( \frac{1}{R_{total}} = \frac{1}{5Ω} + \frac{1}{5Ω} = \frac{2}{5Ω} \Rightarrow R_{total} = 2.5Ω
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