In USA Today (Sept. 5, 1996) 5the results of a survey involving the use of sleepwear while traveling were listed as follows: Male Female Total Underwear 0.250 0.076 0.326 Nightgown 0.002 0.218 0.220 Nothing 0.160 0.073 0.233 Pajamas 0.046 0.088 0.134 T-shirt 0.084 0.003 0.087 (a) What is the probability that a traveler is female who sleeps in nightgown? (b) What is the probability that a traveler is female? (c) Assuming the traveler is a female, what is the probability that she sleeps in nude? (d) What is the probability that a traveler is female if she sleeps in pajamas or a T-shirt?

In USA Today (Sept. 5, 1996) 5the results of a survey involving the use of sleepwear while traveling were listed as follows: Male Female Total Underwear 0.250 0.076 0.326 Nightgown 0.002 0.218 0.220 Nothing 0.160 0.073 0.233 Pajamas 0.046 0.088 0.134 T-shirt 0.084 0.003 0.087 (a) What is the probability that a traveler is female who sleeps in nightgown? (b) What is the probability that a traveler is female? (c) Assuming the traveler is a female, what is the probability that she sleeps in nude? (d) What is the probability that a traveler is female if she sleeps in pajamas or a T-shirt?

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A First Course in Probability (10th Edition)

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Chapter1: Combinatorial Analysis

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In USA Today (Sept. 5, 1996) 5the results of a survey involving the use of sleepwear while traveling were listed as follows:

Male Female Total

Underwear 0.250 0.076 0.326

Nightgown 0.002 0.218 0.220

Nothing 0.160 0.073 0.233

Pajamas 0.046 0.088 0.134

T-shirt 0.084 0.003 0.087

(a) What is the probability that a traveler is female who sleeps in nightgown?

(b) What is the probability that a traveler is female?

(d) What is the probability that a traveler is female if she sleeps in pajamas or a T-shirt?

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