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in this solution i need to explain how values ​​are found h(w) and g(w) How did you turn into a tan? Where did it come from -90

in this solution i need to explain how values ​​are found h(w) and g(w) How did you turn into a tan? Where did it come from -90

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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in this solution

i need to explain how values ​​are found

h(w) and g(w)

How did you turn into a tan?

Where did it come from -90

801 Kv ки Overall transfer function G(S) 1+ GCS) HCS) CCS) RCS) (CS) = Gls) = 10 G₁ (S) S(5+1) RCS) = Here, H(S) =1 1 => Kv = 20/sec 10 Gc PM = SCHS) =) 50 1+ 10 G₁ - lem SG(s)H(S) 5-70 10 Gc lim s. 10 Ge 570 Kv = lem 10Gc 5-70 S+1 S(5+1) SCS+1)+10GC 5(5+1) => Kv = 20 then Ge=2 Kv = 10 (₂) and for a phate margin of 50⁰° = 10Gc tań w = 40 <= 20 180 + (H(W) Gew) 180 + [90 [-90 - tailw] tanyi =0.83 •W=Wgc So, for this lead Compensator Gc= 2₁ w = 0.83 rad/s rad/see
Transcribed Image Text:801 Kv ки Overall transfer function G(S) 1+ GCS) HCS) CCS) RCS) (CS) = Gls) = 10 G₁ (S) S(5+1) RCS) = Here, H(S) =1 1 => Kv = 20/sec 10 Gc PM = SCHS) =) 50 1+ 10 G₁ - lem SG(s)H(S) 5-70 10 Gc lim s. 10 Ge 570 Kv = lem 10Gc 5-70 S+1 S(5+1) SCS+1)+10GC 5(5+1) => Kv = 20 then Ge=2 Kv = 10 (₂) and for a phate margin of 50⁰° = 10Gc tań w = 40 <= 20 180 + (H(W) Gew) 180 + [90 [-90 - tailw] tanyi =0.83 •W=Wgc So, for this lead Compensator Gc= 2₁ w = 0.83 rad/s rad/see
Q2] Consider the system shown in Figure (1). Design a compensator such that the closed-loop system will satisfy the requirements that the static velocity error constant K₁ is 20 sec-¹, phase margin is 50°, and gain margin is not less than 10 dB. Verify the compensator to satisfy the requirements. R(s) Input (+ Gc(s) Figure (1) 10 s(s+1) [15 Marks] Y(s) Output
Transcribed Image Text:Q2] Consider the system shown in Figure (1). Design a compensator such that the closed-loop system will satisfy the requirements that the static velocity error constant K₁ is 20 sec-¹, phase margin is 50°, and gain margin is not less than 10 dB. Verify the compensator to satisfy the requirements. R(s) Input (+ Gc(s) Figure (1) 10 s(s+1) [15 Marks] Y(s) Output
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