In this section, we study the effect of a fluid resistive force on oscillatory motion. We observe a horizontal block/spring system as shown in the simulation "The Damped Oscillator". Run the animation now. The block of mass m = 100 g is on a horizontal, frictionless surface. The block is connected to one end of a spring of spring constant k. The other end of the spring is fixed. The location of the block when in equilibrium is at x = 0. A vertical sail is connected to the block so that when the block moves, a damping force due to drag with the air acts on the block. In this section, we assume the block moves slowly enough that the fluid drag force is linearly proportional to the velocity and opposite in direction, as described by the mathematical expression Fa = - bu where the nonnegative constant b has units of N/(m/s), and the size of b depends on properties of both the sail and the fluid, which in this case is air.

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In this section, we study the effect of a fluid resistive force on oscillatory motion. We observe a horizontal block/spring system as
shown in the simulation "The Damped Oscillator". Run the animation now. The block of mass m = 100 g is on a horizontal,
frictionless surface. The block is connected to one end of a spring of spring constant k. The other end of the spring is fixed. The
location of the block when in equilibrium is at x 0. A vertical sail is connected to the block so that when the block moves, a damping
force due to drag with the air acts on the block. In this section, we assume the block moves slowly enough that the fluid drag force is
linearly proportional to the velocity and opposite in direction, as described by the mathematical expression
=
Ed
=
- bu
where the nonnegative constant b has units of N/(m/s), and the size of b depends on properties of both the sail and the fluid, which in
this case is air.
Transcribed Image Text:In this section, we study the effect of a fluid resistive force on oscillatory motion. We observe a horizontal block/spring system as shown in the simulation "The Damped Oscillator". Run the animation now. The block of mass m = 100 g is on a horizontal, frictionless surface. The block is connected to one end of a spring of spring constant k. The other end of the spring is fixed. The location of the block when in equilibrium is at x 0. A vertical sail is connected to the block so that when the block moves, a damping force due to drag with the air acts on the block. In this section, we assume the block moves slowly enough that the fluid drag force is linearly proportional to the velocity and opposite in direction, as described by the mathematical expression = Ed = - bu where the nonnegative constant b has units of N/(m/s), and the size of b depends on properties of both the sail and the fluid, which in this case is air.
Reset the animation. Set the damping to zero, b = 0. Run the animation again. Use information in the plot of
x(t) to determine the spring constant k.
k = i
It is useful to define a new constant ß with SI units of radians per second, ß = b/(2m). What value of b corresponds to
BlwSHM
0.25? Things to note: (1) @SHM = √k/m is the angular frequency in the absence of damping; (2) you
found the value of k in question 1; (3) you are given that m = 100 g
b =
N/(m/s)
=
Using the expression x(t)
case where p/@SHM
x(t) =
= xmе-Bt
N/m
= 0.25.
cos (@'t + p)calculate the displacement x(t) of the oscillator at t = 2.50 sfor the
m
Transcribed Image Text:Reset the animation. Set the damping to zero, b = 0. Run the animation again. Use information in the plot of x(t) to determine the spring constant k. k = i It is useful to define a new constant ß with SI units of radians per second, ß = b/(2m). What value of b corresponds to BlwSHM 0.25? Things to note: (1) @SHM = √k/m is the angular frequency in the absence of damping; (2) you found the value of k in question 1; (3) you are given that m = 100 g b = N/(m/s) = Using the expression x(t) case where p/@SHM x(t) = = xmе-Bt N/m = 0.25. cos (@'t + p)calculate the displacement x(t) of the oscillator at t = 2.50 sfor the m
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