In this question, you are asked to investigate the following improper integral: (х-3) -13 dx 10.1 Firstly, one must split the integral as the sum of two integrals, i.e. 9 (x-3 )-1/3dx + lim (х-3) -13dx I= lim for what value of c? c = 10.2 Below, we will call the two integrals we split I into, I, and I. Now find an antiderivative of the integrand of I, (and I, and I), i.e. a function F(x), which when evaluated at the limits of Ig, will give the value of Ig. F(x) = 10.3 Now evaluate F(x) at each of the limits for I, and hence give the value of Ig. Note. By I, we mean the integral with an s limit, before the limit s c is taken. I, = 10.4 Now take the limit as s c, where c is your answer to the first part. If I, diverges as s c, enter u (for undefined), or if I, converges, enter the value to which I, converges.

In this question, you are asked to investigate the following improper integral: (х-3) -13 dx 10.1 Firstly, one must split the integral as the sum of two integrals, i.e. 9 (x-3 )-1/3dx + lim (х-3) -13dx I= lim for what value of c? c = 10.2 Below, we will call the two integrals we split I into, I, and I. Now find an antiderivative of the integrand of I, (and I, and I), i.e. a function F(x), which when evaluated at the limits of Ig, will give the value of Ig. F(x) = 10.3 Now evaluate F(x) at each of the limits for I, and hence give the value of Ig. Note. By I, we mean the integral with an s limit, before the limit s c is taken. I, = 10.4 Now take the limit as s c, where c is your answer to the first part. If I, diverges as s c, enter u (for undefined), or if I, converges, enter the value to which I, converges.

Name: Need answer for the number 10 question in the picture In this question
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Description: Need answer for the number 10 question in the picture In this question, you are asked to investigate the following improper integral:9I=(х-3) -13dx10.1Firstly, one must split the integral as the sum of two integrals, i.e.I= lim(х-3) -13dx-lim(х-3) -1