13Problem 1BIn this problem we want to do an "in-place" sorting, that is, given an unsorted array, sort the array directly,by swapping elements on the array, without using and returning another array.Here is the main idea: first scan through the original input array from index 0 to the end, finding the smallestelement. This element should be the first element of the sorted array. To make it the first element of the array, thealgorithm swaps the smallest element with the element at index 0. Now, subarray at index 0 is considered the sortedarray, and the rest is unsorted. Next, scan through the unsorted part of the array, from index 1 to the end,finding the smallest element in the range. Then make it the 2nd element of the array by swapping it with the elementat index 1. Now subarray at index 0 and index 1 are sorted, and the rest are unsorted. Next, scan through the unsortedpart of thepart of the array from index 2 to the end, finding the smallest element and put it as the 3rd element of the array.Repeat the process until no more unsorted subarray exists. Following figure shows the steps of sorting an array.swap.2972 981387 66 52513613 is smallest-swap1372982987665251 3629 is smallestswapIn each iteration,subarray to the leftof the orange132998728766 52 513636 is smallestswap.13 2936728766 525198S1 is smallestswapelement is sorted.7298S2 is smallestFrom orange13293651876652no swapelement to the end87 72 9866 is smallestno swappingis the unsortedsubarray2936515266Ldems-13 2936 51 52 6687729872 is smallestno swap9852 66 | 72 |8787 is smallestno swapping13 2936 5113 2936 5152 66728798sorting completed Develop flowchart for this in-place sorting algorithm,Hint: you will need nested loops for doing the work in one algorithm.For swapping two elements, create a variable temp to hold one of the values temporarily.Save the flowchart as img_01B.jpg• Implement the algorithm using JavaScriptComplete function problemlB() in JS file, attach the onclick event to the corresponding html buttonYour implementation should match your flowchartSample output (each run will generate a different input array)49,71,85,19,29,43,20,78,29,4019,20, 29, 29, 40, 43, 49,71, 78,85problem1A- aroy sortproblem18 array sort [in-place]problermB array searchproblem3A-- string compare (same length]problem38 string compare

In this problem we want by swapping elements o Here is the main idea: fi element. This element sl algorithm swaps the sma part of the array, and the finding the smallest eler at index 1. Now subarra part of the array from in Repeat the process until

In this problem we want by swapping elements o Here is the main idea: fi element. This element sl algorithm swaps the sma part of the array, and the finding the smallest eler at index 1. Now subarra part of the array from in Repeat the process until

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Counting sort

The counting sort algorithm sorts an array’s contents by counting the repetition of each element that occurs in the array. A counting sort algorithm is a stable algorithm that works the best when the range of elements in the array is small, say for example from 0 to 9. The count which is the number of repetitions of an element in the array is mapped to an index of an auxiliary array, which is then saved in an auxiliary array. The counting sort algorithm has a stable time complexity of the order of O(size of array + size of auxiliary array). Let’s discuss the algorithm in detail as follows.

Question

13
Problem 1B
In this problem we want to do an "in-place" sorting, that is, given an unsorted array, sort the array directly,
by swapping elements on the array, without using and returning another array.
Here is the main idea: first scan through the original input array from index 0 to the end, finding the smallest
element. This element should be the first element of the sorted array. To make it the first element of the array, the
algorithm swaps the smallest element with the element at index 0. Now, subarray at index 0 is considered the sorted
array, and the rest is unsorted. Next, scan through the unsorted part of the array, from index 1 to the end,
finding the smallest element in the range. Then make it the 2nd element of the array by swapping it with the element
at index 1. Now subarray at index 0 and index 1 are sorted, and the rest are unsorted. Next, scan through the unsorted
part of the
part of the array from index 2 to the end, finding the smallest element and put it as the 3rd element of the array.
Repeat the process until no more unsorted subarray exists. Following figure shows the steps of sorting an array.
swap.
29
72 98
13
87 66 52
51
36
13 is smallest
-swap
13
72
98
29
87
66
52
51 36
29 is smallest
swap
In each iteration,
subarray to the left
of the orange
13
29
98
72
87
66 52 51
36
36 is smallest
swap.
13 29
36
72
87
66 52
51
98
S1 is smallest
swap
element is sorted.
72
98
S2 is smallest
From orange
13
29
36
51
87
66
52
no swap
element to the end
87 72 98
66 is smallest
no swapping
is the unsorted
subarray
29
36
51
52
66
Ldems-
13 29
36 51 52 66
87
72
98
72 is smallest
no swap
98
52 66 | 72 |87
87 is smallest
no swapping
13 29
36 51
13 29
36 51
52 66
72
87
98
sorting completed

Develop flowchart for this in-place sorting algorithm,
Hint: you will need nested loops for doing the work in one algorithm.
For swapping two elements, create a variable temp to hold one of the values temporarily.
Save the flowchart as img_01B.jpg
• Implement the algorithm using JavaScript
Complete function problemlB() in JS file, attach the onclick event to the corresponding html button
Your implementation should match your flowchart
Sample output (each run will generate a different input array)
49,71,85,19,29,43,20,78,29,40
19,20, 29, 29, 40, 43, 49,71, 78,85
problem1A- aroy sort
problem18 array sort [in-place]
problermB array search
problem3A-- string compare (same length]
problem38 string compare

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