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In this problem we use the change of variables x = 5s + t. y = 8s - t to compute the integral S(x + y) dA, where R is the parallelogram with vertices (x, y) = (0,0). (10, 2) (13,-1), and (3,-3). First find the magnitude of the Jacobian, Then, with a = C= SR(z+y) dA=ff( and d = a(z,y) 8(s,t) b= 8+ = 6 t+ dt ds =

In this problem we use the change of variables x = 5s + t. y = 8s - t to compute the integral S(x + y) dA, where R is the parallelogram with vertices (x, y) = (0,0). (10, 2) (13,-1), and (3,-3). First find the magnitude of the Jacobian, Then, with a = C= SR(z+y) dA=ff( and d = a(z,y) 8(s,t) b= 8+ = 6 t+ dt ds =

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In this problem we use the change of variables x = 58+ t, y = 8-t to compute the integral S(x + y) dA, where R is the parallelogram with vertices (x, y) = (0,0), (10, 2). (13,-1), and (3, -3). First find the magnitude of the Jacobian, Then, with a = C= SR(x + y) dA=ff( and d = 8(x,y) (s,t) b= 8+ = 6 t+ ) dt ds = |
Transcribed Image Text:In this problem we use the change of variables x = 58+ t, y = 8-t to compute the integral S(x + y) dA, where R is the parallelogram with vertices (x, y) = (0,0), (10, 2). (13,-1), and (3, -3). First find the magnitude of the Jacobian, Then, with a = C= SR(x + y) dA=ff( and d = 8(x,y) (s,t) b= 8+ = 6 t+ ) dt ds = |
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