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In this experiment, you need to determine the refractive index of the end product "n-butyl acetate" at room temperature. The literature value is provided at 20 0C. In order to confirm the purity of the product, you need to compare the literature and experimental refractive indices at same temperature. If the experimental refractive index of the end product is found to be 1.3937 at 25.6 0C, convert this value at 20 0C. (Answer require 4 decimal places) Hint:  ∆n    =  ∆T (-0.00045) ∆T  =  T2 – T1  where T2 = Final temperature at which you want to calculate refractive index value    T1 = Temperature at which refractive index is known

In this experiment, you need to determine the refractive index of the end product "n-butyl acetate" at room temperature. The literature value is provided at 20 0C. In order to confirm the purity of the product, you need to compare the literature and experimental refractive indices at same temperature. If the experimental refractive index of the end product is found to be 1.3937 at 25.6 0C, convert this value at 20 0C. (Answer require 4 decimal places) Hint:  ∆n    =  ∆T (-0.00045) ∆T  =  T2 – T1  where T2 = Final temperature at which you want to calculate refractive index value    T1 = Temperature at which refractive index is known

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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 In this experiment, you need to determine the refractive index of the end product "n-butyl acetate" at room temperature. The literature value is provided at 20 0C. In order to confirm the purity of the product, you need to compare the literature and experimental refractive indices at same temperature. If the experimental refractive index of the end product is found to be 1.3937 at 25.6 0C, convert this value at 20 0C.

(Answer require 4 decimal places)

Hint: 

∆n    =  ∆T (-0.00045)

∆T  =  T2 – T1

 where

T2 = Final temperature at which you want to calculate refractive index value  

 T1 = Temperature at which refractive index is known

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