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In this exercise you will use Laplace transforms to solve the differential equation y"+25y = 0, y(0) = 0, y'(0) = 6. Find the Laplace transform of each term in the equation. Your answer(s) may contain L(y). Incorporate any initial conditions if necessary. L(y'"') = s²L(y) — 6 25L (y) L(25y) L(0) = 0 Good job! You now have the equation s²L(y) — 6+25L(y) = 0. Use factoring and algebra to solve this equation for L(y). L(y) = = Part 1 of 3 Part 2 of 3

In this exercise you will use Laplace transforms to solve the differential equation y"+25y = 0, y(0) = 0, y'(0) = 6. Find the Laplace transform of each term in the equation. Your answer(s) may contain L(y). Incorporate any initial conditions if necessary. L(y'"') = s²L(y) — 6 25L (y) L(25y) L(0) = 0 Good job! You now have the equation s²L(y) — 6+25L(y) = 0. Use factoring and algebra to solve this equation for L(y). L(y) = = Part 1 of 3 Part 2 of 3

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Homework 9: Question 4

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In this exercise you will use Laplace transforms to solve the differential equation y"+25y = 0, y(0) = 0, y'(0) = 6. Find the Laplace transform of each term in the equation. Your answer(s) may contain L(y). Incorporate any initial conditions if necessary. L(y') = s²L(y) - 6 L(25y) 25L(y) L(0) = 0 Good job! You now have the equation s²L(y) — 6 + 25L(y) = 0. - Use factoring and algebra to solve this equation for L(y). L(y) = Part 1 of 3 Part 2 of 3
Transcribed Image Text:In this exercise you will use Laplace transforms to solve the differential equation y"+25y = 0, y(0) = 0, y'(0) = 6. Find the Laplace transform of each term in the equation. Your answer(s) may contain L(y). Incorporate any initial conditions if necessary. L(y') = s²L(y) - 6 L(25y) 25L(y) L(0) = 0 Good job! You now have the equation s²L(y) — 6 + 25L(y) = 0. - Use factoring and algebra to solve this equation for L(y). L(y) = Part 1 of 3 Part 2 of 3
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