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In this exercise, we suggest the use of technology. Round all answers to two decimal places. Minimize c = 5.5x + y + 1.8z + w subject to + w > 1,000 z + w > 2,000 S 700 x 2 0, y 2 0, z 2 0, w 2 0. 5.12x - y 1.13x + y C = (x, y, z, w) = (

In this exercise, we suggest the use of technology. Round all answers to two decimal places. Minimize c = 5.5x + y + 1.8z + w subject to + w > 1,000 z + w > 2,000 S 700 x 2 0, y 2 0, z 2 0, w 2 0. 5.12x - y 1.13x + y C = (x, y, z, w) = (

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In this exercise, we suggest the use of technology. Round all answers to two decimal places. Minimize c = 5.5x + y + 1.8z + w subject to + w 2 1,000 z + w> 2,000 < 700 x 2 0, y 2 0, z > 0, w > 0. 5.12х - у 1.13x + y C = (х, у, z, w) %3D
Transcribed Image Text:In this exercise, we suggest the use of technology. Round all answers to two decimal places. Minimize c = 5.5x + y + 1.8z + w subject to + w 2 1,000 z + w> 2,000 < 700 x 2 0, y 2 0, z > 0, w > 0. 5.12х - у 1.13x + y C = (х, у, z, w) %3D
In this exercise, we suggest the use of technology. Round all answers to two decimal places. Maximize p = 2.2x + 2y + 1.1z + 2w subject to x + 1.5y + 1.5z + 2х + 1.5y — x + 1.5y + x 2 0, y 2 0, z > 0, w 2 0. W< 57.5 z - 10 z + 1.5w > 24 p = (х, у, z, w) %3
Transcribed Image Text:In this exercise, we suggest the use of technology. Round all answers to two decimal places. Maximize p = 2.2x + 2y + 1.1z + 2w subject to x + 1.5y + 1.5z + 2х + 1.5y — x + 1.5y + x 2 0, y 2 0, z > 0, w 2 0. W< 57.5 z - 10 z + 1.5w > 24 p = (х, у, z, w) %3
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