In this circuit below, the Q₁, Q₂ operate in the active region. VDD = 10V, Rs = 15k№, RC1 = RC2 = 10k, RE1 = RE2 = 3.3k and r = co Q₁: B = 120, VBE = 0.7V Q2: B = 120, VBE = 0.7V +10V RE2 Rc1 R₁=47k Rs ww 15k Vs R₂-25k RE1 Rc2 i). Identify the small-signal amplifier configurations ii). Estimate the DC bias voltages and current (I₁, I₂ V₁₁) iii). Calculate the small-signal gain. ** solution with reasonable assumptions to save time. Vi Q₁ ww O VOUT Note: in this question, you should approximate the

In this circuit below, the Q₁, Q₂ operate in the active region. VDD = 10V, Rs = 15k№, RC1 = RC2 = 10k, RE1 = RE2 = 3.3k and r = co Q₁: B = 120, VBE = 0.7V Q2: B = 120, VBE = 0.7V +10V RE2 Rc1 R₁=47k Rs ww 15k Vs R₂-25k RE1 Rc2 i). Identify the small-signal amplifier configurations ii). Estimate the DC bias voltages and current (I₁, I₂ V₁₁) iii). Calculate the small-signal gain. ** solution with reasonable assumptions to save time. Vi Q₁ ww O VOUT Note: in this question, you should approximate the

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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3. MOSFET diff pair with 2 mA tail current Iss and 5kOhm drain resistors Ro. Kn = 1 mA/N, VIN=2V, lambda is negligible. Positive supply (VDD) is 10V, negative supply is -10v. Fill out the following table: Vin1 Vin2 Vin(diff) VD1 = Vx VD2 = Vy Vo(diff) = Vx-Vy Vs1=Vs2 =Vin1-Vin2 -3 1 1 -1 -1 +1 -1 -1 1 VDD Rp ERD Y M1 M2 Is
In the circuit given in the figure, VT = 25mV, | VBE | = 0.7V, R1 = 1519.62Kohm, R2 = 48.01Kohm, R3 = 3.22Kohm, R4 = 1.38Kohm, VCC = 13.00V, VEE = -6.00V, VA = 19.82V, Since Beta = 163.00, Rs = 23.65 ohm, Ry = 18.08Kohm, by Source calculate IC current, Ri, R0 and voltage gain (V0 / V1) with full analysis.
Redraw the JFET in the figure below showing how to connect a bias voltage between the gate and source. +VDD Rp
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In the circuit given in the figure VT = 25mV, | VBE | = 0.7V, R1 = 950.31Kohm, R2 = 22.50Kohm, R3 = 2.51Kohm, R4 = 1.08Kohm, VCC = 13.00V, VEE = 3.00V, VA = 13.08V, Beta Since = 193.00, Rs = 22.94ohm, Ry = 14.49Kohm, calculate the IC current, Ri, R0 and the voltage gain according to the Source (V0 / V1) by making full analysis. When making your transactions, 2 steps will be taken after the point. Select the closest option according to +/- 10% margin of error. There is only one correct answer to the question.
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Q-2: Explain the saturation of a transistor. Find the given unknowns for the figure below. a. Rc. b. Rg c. Rp. d. VCE e. V Also find the voltage V, at cutoff. 12 V 2 mA Rc 7.6 V V B-80 024 V Q-3: Define Lso and lao, How are they related? Find the following f le corresponding to V = +750mv and Va = +5V
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In the circuit given in the figure VT = 25mV, | VBE | = 0.7V, R1 = 515.22Kohm, R2 = 10.89Kohm, R3 = 2.41Kohm, R4 = 1.03Kohm, VCC = 12.00V, VEE = 2.00V, VA = 12.51V, Beta Since = 107.00, Rs = 23.19ohm, Ry = 8.18Kohm, calculate the IC current, Ri, R0 and voltage gain according to the Source (V0 / V1) by making full analysis.
C6 Shown in Figure C6 is a common emitter amplifier. Follow the specification below and calculate the value of R1 given the information provided. RC Voe vce Vbe vcc = 10 V, VE=1 v, VBE = 0.7 V, IC = 2 mA, B = 100, I(R1) = 10XIB, V(RC) = VCE = 4.5 v RI RL Ve Vbb Figure C6 Common Emitter amplifier with Potentiometer Bias A. No answers below are correct B. R1 = 13.5 ko C. R1 = 21.6 kO D. R1 = 8.5 kn
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