In the world series of baseball, two teams A & B play a sequence of games against each other and the first team that wins a total of four games become the winner of the world series. If the probability that team A will win any parties game against team B is 1/3, what's the probability that team A will win the world series?

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In the world series of baseball, two teams A & B play a sequence of games against each other and the first team that wins a total of four games become the winner of the world series. If the probability that team A will win any parties game against team B is 1/3, what's the probability that team A will win the world series?
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Given that, the probability that team A will win any parties game against team B is 1/3 i.e. 

p= 1/3

Team A wins if it wins the majority of 7 games

Thus, we've to compute the probability of winning 4, 5, 6 or 7 games out of 7. 

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