In the US, systolic blood pressure is a random variable that is normally distributed with a mean of 121mmHg and a standard deviation of 14.5 mmHg. Let X be the systolic blood pressure of a randomly selectedpatient.1. Describe the probability distribution of X and state its parameters μ and o:X - Select an answer (μ =], 0 = |2. Find the probability that the systolic blood pressure of a randomly selected patient isa. less than 147 mmHg.(Round the answer to 4 decimal places)b. between 160 and 161 mmHg.c. more than 153 mmHg.(Round the answer to 4 decimal places)(Round the answer to 4 decimal places)3. Find the 50-th percentile for the systolic blood pressure.decimal place)mmHg (Round the answer to 1

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Answered: In the US, systolic blood pressure is a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A government sample survey plans to measure the total cholesterol level of an SRS of men aged 20-34. suppose that, in fact, the total cholesterol level of men aged 20-34 follows the normal distribution with a mean of 182 milligrams per deciliter. The standard deviation is 37 milligrams per deciliter. choose an SRS of 1000 men from this population. Now what is the probability that x falls within + or - 2 milligrams per deciliter of the mean?
Assume that the probability of a being born with Genetic Condition B is p=p=13/60. A study looks at a random sample of 290 volunteers.Find the most likely number of the 290 volunteers to have Genetic Condition B.(Round answer to one decimal place.)μ = Let XX represent the number of volunteers (out of 290) who have Genetic Condition B. Find the standard deviation for the probability distribution of XX.(Round answer to two decimal places.)σ = Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.Enter answer as an interval using square-brackets only with whole numbers.usual values =
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The random variable x represents the number of boys in a family of three children. Assuming that boys and girls are equally likely, find the mean and standard deviation for the random variable x P(x) 0.125 0.375 2. 0.375 0.125 3. OA. mean: 1.50; standard deviation: 0.76 OB. mean: 2.25, standard deviation: 0.76 OC. mean: 1.50; standard deviation: 087 OD. mean 2.25, standard deviation 0 87 Click to select your anewer Type here to search 4.
Suppose that the weight of an newborn fawn is Uniformly distributed between 2.2 and 3.9 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. The mean of this distribution is . The standard deviation is . The probability that fawn will weigh exactly 2.5 kg is P(x=2.5)=P(x=2.5)= . The probability that a newborn fawn will be weigh between 2.6 kg and 3.7 kg is P(2.6<x<3.7)=P(2.6<x<3.7)= . The probability that a newborn fawn will be weigh more than 3.24 kg is P(x>3.24)=P(x>3.24)= . P(x>2.8∣x<3.3)=P(x>2.8∣x<3.3)= . Find the 45th percentile. kg
The random variable x represents the number of boys in a family of three children. Assuming that boys and girls are equally likely, find the mean and standard deviation for the random variable x. X P(x) 0 0.125 1 0.375 2 0.375 3 0.125 O A. mean: 1.50; standard deviation: 0.87 OB. mean: 1.50; standard deviation: 0.76 O C. mean: 2.25; standard deviation: 0.87 O D. mean: 2.25; standard deviation: 0.76 C
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose per deciliter of blood. After a 12-hour fast, the random variable x will have a distribution that is approximately normal with μ = 85 and σ = 25. After 50 years of age, both the mean and standard deviation tend to increase. What is the probability that, for an adult under 50 years old, after a 12-hour fast, x is less than 130?
Let x be a random variable that represents red blood cell count (RBC) in millions of cells per cubic millimeter of whole blood. Then x has a distribution that is approximately normal. For the population of healthy female adults, suppose the mean of the x distribution is about 4.78. Suppose that a female patient has taken six laboratory blood tests over the past several months and that the RBC count data sent to the patient's doctor are as follows. 4.9 4.2 4.5 4.1 4.4 4.3 (i) Use a calculator with sample mean and standard deviation keys to find x and s. (Round your answers to two decimal places.) x = s = (ii) Do the given data indicate that the population mean RBC count for this patient is lower than 4.78? Use ? = 0.05. (a) What is the level of significance?State the null and alternate hypotheses. H0: ? < 4.78; H1: ? = 4.78H0: ? = 4.78; H1: ? ≠ 4.78 H0: ? = 4.78; H1: ? < 4.78H0: ? = 4.78; H1: ? > 4.78H0: ? > 4.78; H1: ? = 4.78 (b) What sampling…
Assume that the probability of a being born with Genetic Condition B is π=π=14/15. A study looks at a random sample of 173 volunteers.Find the most likely number of the 173 volunteers to have Genetic Condition B. (Round answer to one decimal place.) μ = Let XX represent the number of volunteers (out of 173) who have Genetic Condition B. Find the standard deviation for the probability distribution of XX. (Round answer to two decimal places.) σ = Use the range rule of thumb to find the minimum usual value μ-2σ and the maximum usual value μ+2σ.Enter answer as an interval using square-brackets only with whole numbers. ? Round your answer to one decimal place.usual values =
Service time for a customer coming through a checkout counter in a retail store is a random variable with the mean of 4.0 minutes and standard deviation of 2.0 minutes. Suppose that the distribution of service time is fairly close to a normal distribution. Suppose there are two counters in a store, n₁ = 46 customers in the first line and n₂ = 52 customers in the second line. Find the probability that the difference between the mean service time for the shorter line X₁ and the mean service time for the longer one X₂ is more than 0.3 minutes. Assume that the service times for each customer can be regarded as independent random variables. Round your answer to two decimal places (e.g. 98.76). P = !
The percent of fat calories that a person consumes each day is normally distributed with a mean of about 35 and a standard deviation of about ten. Suppose that 9 individuals are randomly chosen. Let X = average percent of fat calories. For the group of 9, find the probability that the average percent of fat calories consumed is more than six. (Round your answer to four decimal places.)
Dandelions have effects on crop production and lawn growth and are studied. In one region, the mean number of dandelions per square meter was found to be 10.8.Find the probability of no dandelions in an area of 1 m².P(X=0)=P(X=0)= Find the probability of at least one dandelion in an area of 1 m².P(at least one) = Find the probability of at most two dandelions in an area of 1 m².P(X≤2)=P(X≤2)=

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