In the two-slit interference , the slitwidths are each 12.0 mm,their separation is 24.0 mm,the wavelength is600 nm, and the viewing screen is at a distance of 4.00 m. Let IP representthe intensity at point P on the screen, at height y = 70.0 cm. (a)What is the ratio of IP to the intensity Im at the center of the pattern?(b) Determine where P is in the two-slit interference pattern by givingthe maximum or minimum on which it lies or the maximum and minimumbetween which it lies. (c) In the same way, for the diffraction thatoccurs, determine where point P is in the diffraction pattern.

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A: Let the slit width = d Wavelength (λ) = 622 nm θ1,minimum = 21o

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A: Given data: The angle, θ=21.2° Slit width, d=3.95 μm=3.95×10-6 m  m = 3

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Q: Plz don't use chat gpt Chatgpt means downvote

A: Part c:

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A: As per our policy, we will answer the first 3. Kindly resubmit the question for the other answers.…

Interference of Light

The word "constructive" signifies addition in interference. Constructive interference occurs when the path of the waves that start from the slit differs by 1 entire wavelength or in the intervals of the same. Hence, the waves that are presented on the screen are in phase (crest to crest/trough to trough). The waves interfering constructively forms bright fringes on the screen.