In the theory of splines, we try to find simple (quadratic or cubic) curves that pass through given points, and fit together to form smooth (differentiable) curves. Suppose we want to fit quadratic curves together through the points A=(0,1), B= [1,3), C = [2, 4] and D= [3,4]. Move the points C and D in the GeoGebra' app below to their specified locations. Let's suppose the first quadratic (blue) is given by f(x)=2x2+1 on the interval [0, 1]. You can easily verify that the curve passes through points A and B. Our second quadratic (red) is of the form g(z) = az²+bx+c and must pass through points B and C and have the same derivative as f(z) at B (remember to move C to the point (2,4)). Then g(z) -3x2+10°x-4 Similarly (remembering that D is located at [3,4]) the third quadratic (black) defined on the interval [2, 3) must be h(z)

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In the theory of splines, we try to find simple (quadratic or cubic) curves that pass through given points, and fit
together to form smooth (differentiable) curves. Suppose we want to fit quadratic curves together through the points
A [0, 1], B = [1,3), C= (2,4) and D= [3,4].
Move the points C and D in the GeoGebra' app below to their specified locations.
B
Q
Let's suppose the first quadratic (blue) is given by f(x)=2x2+1 on the interval [0, 1]. You can easily verify that
the curve passes through points A and B.
Our second quadratic (red) is of the form
g(x) = ax² +be+c
and must pass through points B and C and have the same derivative as f(x) at B (remember to move C to the
point (2,4)). Then
g(x)
-3°x^2+10 x-4
Similarly (remembering that D is located at [3, 4)) the third quadratic (black) defined on the interval [2,3] must be
h(x)
3
Transcribed Image Text:In the theory of splines, we try to find simple (quadratic or cubic) curves that pass through given points, and fit together to form smooth (differentiable) curves. Suppose we want to fit quadratic curves together through the points A [0, 1], B = [1,3), C= (2,4) and D= [3,4]. Move the points C and D in the GeoGebra' app below to their specified locations. B Q Let's suppose the first quadratic (blue) is given by f(x)=2x2+1 on the interval [0, 1]. You can easily verify that the curve passes through points A and B. Our second quadratic (red) is of the form g(x) = ax² +be+c and must pass through points B and C and have the same derivative as f(x) at B (remember to move C to the point (2,4)). Then g(x) -3°x^2+10 x-4 Similarly (remembering that D is located at [3, 4)) the third quadratic (black) defined on the interval [2,3] must be h(x) 3
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