In the shown below circuit, the switch closes at t=0. 50 10 V 5 mH a) What is the difference of potential on the resistor after a very long time? b) What is the difference of potential on the inductor after 3 ms? (round up to 1 decimal digit) c) How much time does it take to store 2.5 mJ in the inductor? (express the time in ms and round up to 1 decimal digit) ell
In the shown below circuit, the switch closes at t=0. 50 10 V 5 mH a) What is the difference of potential on the resistor after a very long time? b) What is the difference of potential on the inductor after 3 ms? (round up to 1 decimal digit) c) How much time does it take to store 2.5 mJ in the inductor? (express the time in ms and round up to 1 decimal digit) ell
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**Circuit Analysis Problem**
1. In the circuit shown below, the switch closes at \( t = 0 \).
![Circuit Diagram"
- **Components:**
- Voltage Source: \( 10 \, \text{V} \)
- Resistor: \( 5 \, \Omega \)
- Inductor: \( 5 \, \text{mH} \)
**Questions:**
a) What is the difference of potential on the resistor after a very long time?
b) What is the difference of potential on the inductor after 3 ms? (Round up to 1 decimal digit)
c) How much time does it take to store 2.5 mJ in the inductor? (Express the time in ms and round up to 1 decimal digit)
**Diagram Explanation:**
The circuit diagram includes a voltage source providing 10 volts connected in series with a resistor of 5 ohms and an inductor of 5 millihenries. When the switch is closed, the circuit allows current to flow through these components.
**Conceptual Notes:**
- **Steady state** is reached when the circuit parameters remain constant over time.
- **Transient analysis** involves calculating the behavior of the circuit shortly after the switch is closed.
- The **energy stored** in an inductor is given by \( E = \frac{1}{2} L I^2 \), where \( E \) is the energy, \( L \) is the inductance, and \( I \) is the current.
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This transcription ensures that students can understand the circuit components, analyze potential differences, and compute energy storage within the specified time frames.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1cfd53d0-8cf3-4e08-8682-e45234c2f04e%2Fa434bbdf-08e0-4e71-9b42-e9addc674b5e%2F79x6ewc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website**
---
**Circuit Analysis Problem**
1. In the circuit shown below, the switch closes at \( t = 0 \).

- **Components:**
- Voltage Source: \( 10 \, \text{V} \)
- Resistor: \( 5 \, \Omega \)
- Inductor: \( 5 \, \text{mH} \)
**Questions:**
a) What is the difference of potential on the resistor after a very long time?
b) What is the difference of potential on the inductor after 3 ms? (Round up to 1 decimal digit)
c) How much time does it take to store 2.5 mJ in the inductor? (Express the time in ms and round up to 1 decimal digit)
**Diagram Explanation:**
The circuit diagram includes a voltage source providing 10 volts connected in series with a resistor of 5 ohms and an inductor of 5 millihenries. When the switch is closed, the circuit allows current to flow through these components.
**Conceptual Notes:**
- **Steady state** is reached when the circuit parameters remain constant over time.
- **Transient analysis** involves calculating the behavior of the circuit shortly after the switch is closed.
- The **energy stored** in an inductor is given by \( E = \frac{1}{2} L I^2 \), where \( E \) is the energy, \( L \) is the inductance, and \( I \) is the current.
---
This transcription ensures that students can understand the circuit components, analyze potential differences, and compute energy storage within the specified time frames.
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