In the setting of the previous question, suppose our disjoint set data structure uses the linked-list representation with the weighted-union heuristic. That is, we merge the smaller list at the end of the larger one case of a tie, do the same as in the previous question by joining the second list to the end of the first list). Similarly, we make 8 new sets. for v in [a, b, c, d, e, f, g, h]: Make-set (v) Then, we perform the following operations (in the order given). 1. Union(f, g) 2. Union(h, f) 3. Union(a, b) 4. Union(c, d) 5. Union(c, e) 6. Union(f, c) 7. Union(a, f) At each union operation, call the list merged to the end of the other the merged list. For instance, at the first operationg is the merged list. At the second union, which one is the merged list? ( Select ] At the third union, which one is the merged list? ( Select ) At the fourth union, which one is the merged list? ( Select ) At the fifth union, which one is the merged list? ( Select ] At the sixth union, which one is the merged list? ( Select ] At the seventh union, which one is the merged list? ( Select ) Suppose the cost of a union operation is the number of pointers changed during it. Which operation was the most expensive one? [ Select ]

In the setting of the previous question, suppose our disjoint set data structure uses the linked-list representation with the weighted-union heuristic. That is, we merge the smaller list at the end of the larger one case of a tie, do the same as in the previous question by joining the second list to the end of the first list). Similarly, we make 8 new sets. for v in [a, b, c, d, e, f, g, h]: Make-set (v) Then, we perform the following operations (in the order given). 1. Union(f, g) 2. Union(h, f) 3. Union(a, b) 4. Union(c, d) 5. Union(c, e) 6. Union(f, c) 7. Union(a, f) At each union operation, call the list merged to the end of the other the merged list. For instance, at the first operationg is the merged list. At the second union, which one is the merged list? ( Select ] At the third union, which one is the merged list? ( Select ) At the fourth union, which one is the merged list? ( Select ) At the fifth union, which one is the merged list? ( Select ] At the sixth union, which one is the merged list? ( Select ] At the seventh union, which one is the merged list? ( Select ) Suppose the cost of a union operation is the number of pointers changed during it. Which operation was the most expensive one? [ Select ]

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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13) A linked list is given and the number of the nodes in this linked list is not known. You have to find the sum of the last "x" nodes of the linked list in a single traversal. Assume that size of the linked list is larger than "x". Explain your approach in brief. What is Big-O notation of this solution?
Find the existence of an intersection between two (singly) connected groups. Give back the intersection component. Keep in mind that reference, not value, is used to identify the junction. This means that they are crossing if the kth node of the first linked list is the identical same node (by reference) as the jth node of the second linked list.
What are the conditions for testing whether a linked list T is empty, if T is a(i) simple singly linked list, (ii) headed singly linked list, (iii) simple circularlylinked list or (iv) headed circularly linked list?
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One of the linked list variants we saw was a singly-linked list with head and tail pointers. Let's consider where this variant fell short and whether there are other ways to improve it besides what we saw. Why isn't the presence of a tail pointer enough to allow us to remove the last node in the list in Θ(1) time? Suppose that we added a third list-level pointer (i.e., outside of the nodes) called beforeTail, which always pointed to the second-to-last node in the list. Would we now be able to remove the last node in the list in Θ(1) time?
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To add the two polynomials, we presume that the singly linked lists have theirnodes arranged in decreasing order of the exponents of the variable x.The objective is to create a new list of nodes representing the sum P1 + P2. Thisis achieved by adding the COEFF fields of the nodes of similar powers of variable xin lists P1 and P2 and adding a new node reflecting this operation in the resultant listP1 + P2. We present below the crux of the procedure.Here, P1 and P2 are the starting pointers of the singly linked lists representingpolynomials P1 and P2. Additionally, PTR1 and PTR2 are two temporary pointersinitially set to P1 and P2, respectively. Write procedural code
In this assignment, you will expand on the information provided in the course to answer the following questions in a 2- to 3-page paper: What is the difference between a singly-linked list and a doubly-linked list? In what situation would you use a singly-linked list over a doubly-linked list? In what situation would you use a doubly-linked list over a singly-linked list? If a node is in a linked list with N nodes, how many nodes will be traversed during a search for the node? Explain the best- and worst-case search scenarios. Explain why a singly-linked list defines a RemoveAfter() function, while a doubly-linked list defines a Remove() function. Could a RemoveAfter() function also be defined for a doubly-linked list? Explain why or why not. Could a Remove() function also be defined for a singly-linked list? Explain why or why not.
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Consider the function f= {(n,n² – 1) such that n<5,n€N}, written in set-builder notation, which defines a set containing a list of ordered pairs. Write the inverse of f as a set in list form containing ordered pairs. O fl={(0,1),(3,2),(8,3),(15,4)} O fl={(0,– 1),(1,0), (2,3),(3,8),(4,15)} ofl={(1,0), (2,3),(3,8),(4,15)} O fl= {(-1,0),(0,1),(3,2),(8,3),(15,4)} o fl={(3,2),(8,3),(15,4)}