In the RSA algorithm, if n is 13 * 17, what is the block size in bits?

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**RSA Algorithm Block Size Analysis**

To find the block size in bits for the RSA algorithm when \( n = 13 \times 17 \), we first calculate the value of \( n \).

1. **Calculate \( n \):**

   \[
   n = 13 \times 17 = 221
   \]

2. **Determine the Block Size:**

   The block size in RSA is based on the number of bits in the value of \( n \).
   - Convert 221 to binary: \( 221_{10} = 11011101_2 \).
   - The binary representation has 8 bits.

Therefore, the block size in bits for \( n = 221 \) is **8 bits**.

This calculation shows how the factors of \( n \) determine its size in binary representation, which directly impacts the block size in RSA encryption.
Transcribed Image Text:**RSA Algorithm Block Size Analysis** To find the block size in bits for the RSA algorithm when \( n = 13 \times 17 \), we first calculate the value of \( n \). 1. **Calculate \( n \):** \[ n = 13 \times 17 = 221 \] 2. **Determine the Block Size:** The block size in RSA is based on the number of bits in the value of \( n \). - Convert 221 to binary: \( 221_{10} = 11011101_2 \). - The binary representation has 8 bits. Therefore, the block size in bits for \( n = 221 \) is **8 bits**. This calculation shows how the factors of \( n \) determine its size in binary representation, which directly impacts the block size in RSA encryption.
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