In the reaction shown below, the species being oxidized is and the species being reduced is NO, (aq) + Cu (s) --> NO (g) + Cu2* (aq)

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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nvas
In the reaction shown below, the species being oxidized is
and the species being reduced is
respec
NO3 (aq) + Cu (s) --> NO (g) + Cu2+ (aq)
1) A pure ("free") element has an oxidation state of 0.
2) The oxidation state for a monatomic ion (e.g. Ca2+, S2-) is equal to the ion
charge.
3) Fluorine has an oxidation state of -1 in all of its compounds.
4) Hydrogen has an oxidation state of +1, except when it is combined with
metals (-1).
5) Oxygen almost always has a -2 oxidation state.
6) Chlorine, bromine, and iodine have a -1 oxidation state, except when
combined with fluorine or oxygen."
O Cu / N3+
O N5+ / Cu
O N°/ Cu2+
O Cu2/N5+
O Cu / NS
*Previous
DELL
国
increasing priority
Transcribed Image Text:nvas In the reaction shown below, the species being oxidized is and the species being reduced is respec NO3 (aq) + Cu (s) --> NO (g) + Cu2+ (aq) 1) A pure ("free") element has an oxidation state of 0. 2) The oxidation state for a monatomic ion (e.g. Ca2+, S2-) is equal to the ion charge. 3) Fluorine has an oxidation state of -1 in all of its compounds. 4) Hydrogen has an oxidation state of +1, except when it is combined with metals (-1). 5) Oxygen almost always has a -2 oxidation state. 6) Chlorine, bromine, and iodine have a -1 oxidation state, except when combined with fluorine or oxygen." O Cu / N3+ O N5+ / Cu O N°/ Cu2+ O Cu2/N5+ O Cu / NS *Previous DELL 国 increasing priority
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