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In the reaction between aqueous.cobalt(Il) chloride with ammonia, the only complex to be formed is the hexaammine species [Co(NH,)J. The six stepwise stability constants, K, -K corresponding to this ligand substitution reaction at 298K, are given below. K, = 1.5 x 10° K, = 1.3 x 10 K, = 3.6 x 10 K, = 7.4 x 10° K 0.4 K = 0.07 Fill in the blanks to provide a balanced equation representing Step 1 of this reaction. *. NH, + * H,0 Calculate the overall stability constant B6 for this reaction. B6 = x 10A Calculate the value of AG° (298K) for the formation of [Co(NH,)". R = 8.314 J'K'moi" AG° = kJmol

In the reaction between aqueous.cobalt(Il) chloride with ammonia, the only complex to be formed is the hexaammine species [Co(NH,)J. The six stepwise stability constants, K, -K corresponding to this ligand substitution reaction at 298K, are given below. K, = 1.5 x 10° K, = 1.3 x 10 K, = 3.6 x 10 K, = 7.4 x 10° K 0.4 K = 0.07 Fill in the blanks to provide a balanced equation representing Step 1 of this reaction. *. NH, + * H,0 Calculate the overall stability constant B6 for this reaction. B6 = x 10A Calculate the value of AG° (298K) for the formation of [Co(NH,)". R = 8.314 J'K'moi" AG° = kJmol

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.40PAE: Because carbonic acid undergoes a second ionization, the student in Exercise 12.39 is concerned that...
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Chemistry In the reaction between aqueous,cobalt(II) chloride with ammonia, the only complex to be formed is the hexaammine species [Co(NH,). The six stepwise stability constants, K, -Kg, corresponding to this ligand substitution reaction at 298K, are given below. K, = 1.5 x 10 K, = 1.3 x 10 K, = 3.6 x 10' K, = 7.4 x 10° K = 0.4 K = 0.07 Fill in the blanks to provide a balanced equation representing Step 1 of this reaction. NH, - H,0 Calculate the overall stability constant B6 for this reaction. B6 = x 10A Calculate the value of AG° (298K) for the formation of [Co((NH,)". R = 8.314 J'K'moi' -1 AG° = kJmol Select whether the following statements are true, false, or cannot be determined (ND). a. Formation of [Co(NH,),1 is a spontaneous process . AS is expected to be positive for this transformation . At low concentrations of ammonia, ligand substitution does not occur 1. The value for K, indicates that the equilibrium mixture contains more products than reactants 2+ e. Based on the value obtained for AG°, the addition of ammonia to Co[(H,O), is a slow process f. As the substitution reaction proceeds, ligand replacement becomes easier
Transcribed Image Text:Chemistry In the reaction between aqueous,cobalt(II) chloride with ammonia, the only complex to be formed is the hexaammine species [Co(NH,). The six stepwise stability constants, K, -Kg, corresponding to this ligand substitution reaction at 298K, are given below. K, = 1.5 x 10 K, = 1.3 x 10 K, = 3.6 x 10' K, = 7.4 x 10° K = 0.4 K = 0.07 Fill in the blanks to provide a balanced equation representing Step 1 of this reaction. NH, - H,0 Calculate the overall stability constant B6 for this reaction. B6 = x 10A Calculate the value of AG° (298K) for the formation of [Co((NH,)". R = 8.314 J'K'moi' -1 AG° = kJmol Select whether the following statements are true, false, or cannot be determined (ND). a. Formation of [Co(NH,),1 is a spontaneous process . AS is expected to be positive for this transformation . At low concentrations of ammonia, ligand substitution does not occur 1. The value for K, indicates that the equilibrium mixture contains more products than reactants 2+ e. Based on the value obtained for AG°, the addition of ammonia to Co[(H,O), is a slow process f. As the substitution reaction proceeds, ligand replacement becomes easier
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